An object can become charged through electron transfer without changing the total charge of an isolated system.
1 Electric Charge and Fields Online Quiz Questions
Use this free practice quiz with 20 questions to review 1 Electric Charge and Fields, test your knowledge, and prepare for your next test or exam.
Two stationary point charges have opposite signs. What is the nature of the force each exerts on the other?
- A
Attractive
- B
Repulsive
- C
Zero
- D
Cannot be determined from the signs
At a point in an electric field, the field direction is the direction of the force on a positive test charge placed there.
- A
True
- B
False
What principle states that the electric field from multiple source charges is found by adding their individual field vectors?
For fixed source charges, Coulomb’s force magnitude is proportional to the of the separation.
Which statement best describes charge quantization for an object?
- A
The net charge must be a positive integer multiple of e.
- B
The net charge must be an integer multiple of e, which can be positive, negative, or zero.
- C
The net charge can have any real value because electrons transfer continuously.
- D
The net charge must be either +e or −e.
Select all statements that correctly describe the electric field.
- A
It is defined as electric force per unit positive test charge.
- B
Its SI unit is the newton per coulomb.
- C
Fields from multiple source charges add vectorially.
- D
Its direction is defined as the force direction on a negative test charge.
Gauss’s law gives the net electric flux through a closed surface as the net enclosed charge divided by .
A uniform electric field of 500N/C crosses a flat surface of area 0.040m2. The angle between the field and the surface’s area vector is 60∘. What is the electric flux through the surface?
- A
0N⋅m2/C
- B
5N⋅m2/C
- C
10N⋅m2/C
- D
20N⋅m2/C
A positive test charge of 2.0×10−3C experiences a force of 0.60N at a point. What is the electric field magnitude at that point? Enter the numerical value in N/C.
Select all statements that correctly describe Gauss’s law and its use.
- A
The net flux through a closed surface is determined by the net charge enclosed.
- B
Charges outside the surface can affect the field on the surface without changing the net flux through it.
- C
The law is especially useful for finding fields when the charge distribution has sufficient symmetry.
- D
The law is valid only for spherical Gaussian surfaces.
At a point near an isolated negative point charge, which way does the electric field point?
- A
Away from the source charge
- B
Toward the source charge
- C
Perpendicular to the line connecting the point and the source
- D
In a direction determined by the test charge’s sign
How does choosing a Gaussian surface that matches a charge distribution’s symmetry help you use Gauss’s law to find the electric field?
For a flat surface in a uniform electric field, the flux is zero when the field is parallel to the surface.
- A
True
- B
False
Two point charges, +4.0μC and +1.0μC, are separated by 0.20m in vacuum. Using ke=8.99×109C2N⋅m2, what is the magnitude of the force between them?
- A
0.090N
- B
0.899N
- C
1.80N
- D
3.60N
Two objects in an isolated system become charged when electrons transfer from one object to the other. Which conclusion must be true?
- A
The total charge of the two-object system changes because electrons move.
- B
Electrons move between the objects, but the total charge of the isolated system remains constant.
- C
The objects must end with equal and opposite charges.
- D
Protons move between the objects, changing the total charge of the system.
A positive point charge and a negative point charge are stationary. What is the direction of the electric force on the negative charge?
- A
Away from the positive charge, because the charges have opposite signs.
- B
Perpendicular to the line joining the charges.
- C
Toward the positive charge, along the line joining the charges.
- D
There is no force because the charges have different signs.
Two point charges remain unchanged while their separation is doubled. By what factor does the magnitude of the Coulomb force change?
- A
It becomes one-fourth as large.
- B
It becomes one-half as large.
- C
It stays the same.
- D
It becomes twice as large.
Two point charges have magnitudes 2.0μC and 3.0μC, and are separated by 0.20m in vacuum. Using ke=8.99×109C2N⋅m2, what is the magnitude of their force, rounded to the nearest 0.01N?
A point charge of +2.0nC is observed at a distance of 0.30m. Using ke=8.99×109N⋅m2/C2, what is the electric-field magnitude, rounded to the nearest 10N/C?