2 Electric Potential and Capacitance

Builds from electric potential and energy to conductors, capacitance, capacitor energy, and the effects of dielectric materials.

Potential, energy, and electric fields

describes the energy associated with a charge’s position in an electric field. expresses this energy per unit charge:

V=Uq,ΔU=qΔV.V=\frac{U}{q}, \qquad \Delta U=q\Delta V.

Potential difference is also called . Its SI unit is the volt, where 1 V=1 J/C1\ \mathrm{V}=1\ \mathrm{J/C}. Potential is a scalar, so contributions from several charges add algebraically. The zero of potential is a choice; for an isolated point charge, it is customary to set the potential to zero at infinity.

For a point charge QQ, the potential at distance rr is

V=14πε0Qr.V=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r}.

For several point charges, add the potential contributions:

V=14πε0∑iQiri.V=\frac{1}{4\pi\varepsilon_0}\sum_i\frac{Q_i}{r_i}.

A charge qq at potential VV has potential energy U=qVU=qV, measured relative to the chosen zero. With zero potential energy at infinite separation, like charges have positive interaction energy and unlike charges have negative interaction energy.

The electric field relates potential at two locations. In a uniform field directed from point AA to point BB over distance dd,

VB−VA=−Ed.V_B-V_A=-Ed.

More generally,

ΔV=−∫ABE⋅dl.\Delta V=-\int_A^B \mathbf{E}\cdot d\mathbf{l}.

The field points toward decreasing potential. The work done by the field on a charge is Wfield=−ΔU=−qΔVW_{\text{field}}=-\Delta U=-q\Delta V. Moving the charge slowly against the field requires an equal amount of external work.

Example. If a +2.0 μC+2.0\ \mathrm{\mu C} charge moves through a potential difference of −5.0 V-5.0\ \mathrm{V}, then

ΔU=qΔV=(2.0×10−6 C)(−5.0 V)=−1.0×10−5 J.\Delta U=q\Delta V=(2.0\times10^{-6}\ \mathrm{C})(-5.0\ \mathrm{V})=-1.0\times10^{-5}\ \mathrm{J}.

The potential energy decreases by 10 μJ10\ \mathrm{\mu J}, so the field does positive work of 10 μJ10\ \mathrm{\mu J}.

Takeaway: Potential is energy per unit charge, and the sign of qΔVq\Delta V tells whether a charge’s potential energy increases or decreases.

Conductors at equilibrium

A conductor contains mobile charges. If an electric field existed inside its conducting material, those charges would move. In , charge has redistributed so that:

  • The electric field inside the conducting material is zero.

  • The conductor’s surface and interior have the same potential; the conductor is an equipotential.

  • Any excess charge resides on the surface.

  • Just outside the surface, the electric field is perpendicular to it. A tangential field component would move surface charges.

These properties explain electrostatic shielding: an empty cavity within a conductor has no electric field when the conductor is in and no charge is placed inside the cavity. Sharp regions can have especially strong fields because surface charge is more concentrated there.

Takeaway: In , a conductor’s interior has no electric field, and its entire surface is at one potential.

Capacitors and

A capacitor consists of two conductors separated by an insulating gap. Equal and opposite charges, +Q+Q and −Q-Q, establish a potential difference ΔV\Delta V. describes the charge stored per unit potential difference:

C=QΔV.C=\frac{Q}{\Delta V}.

depends on the conductors’ geometry and the material between them, not on the particular values of QQ and ΔV\Delta V. Its SI unit is the farad, with 1 F=1 C/V1\ \mathrm{F}=1\ \mathrm{C/V}.

For two large parallel plates of area AA, separated by distance dd, and with small edge effects,

C=ε0Ad.C=\varepsilon_0\frac{A}{d}.

Increasing plate area increases ; increasing the separation decreases it. In this approximation, the field between the plates is nearly uniform, with

E≈ΔVd.E\approx\frac{\Delta V}{d}.

Takeaway: A capacitor’s geometry determines how much charge it stores for a specified potential difference.

Energy stored in a capacitor

Charging a capacitor requires work, which is stored as in its electric field. For charge magnitude QQ, CC, and potential difference ΔV\Delta V, the stored energy can be calculated in three equivalent ways:

UC=12QΔV=Q22C=12C(ΔV)2.U_C=\frac{1}{2}Q\Delta V=\frac{Q^2}{2C}=\frac{1}{2}C(\Delta V)^2.

Choose the form that uses the quantities known in a problem. For example, a capacitor with 4.0 μF4.0\ \mathrm{\mu F}, charged to 12 V12\ \mathrm{V}, stores

UC=12(4.0×10−6 F)(12 V)2=2.88×10−4 J.U_C=\frac{1}{2}(4.0\times10^{-6}\ \mathrm{F})(12\ \mathrm{V})^2=2.88\times10^{-4}\ \mathrm{J}.

For a uniform electric field in vacuum, the field energy density, meaning energy per unit volume, is

uE=12ε0E2.u_E=\frac{1}{2}\varepsilon_0 E^2.

This expresses that stored energy is associated with the electric field, not simply with charge sitting on the plates.

Takeaway: The three energy formulas are equivalent; select one based on whether charge, , or potential difference is known.

Dielectrics and what remains constant

A is an insulating material placed between a capacitor’s conductors. Its molecules or atoms become polarized in the electric field: bound charges shift slightly, creating a field that opposes the original field within the material.

If a uniform completely fills the gap, the becomes

C=κC0=κε0Ad,C=\kappa C_0=\kappa\varepsilon_0\frac{A}{d},

where C0C_0 is the vacuum and κ\kappa is the , or relative permittivity. For common linear dielectrics, κ>1\kappa>1, so the increases.

The resulting changes depend on whether the capacitor remains connected to a battery:

  • Disconnected capacitor: Its charge QQ stays constant. As CC increases, ΔV=Q/C\Delta V=Q/C decreases, and the stored energy U=Q2/(2C)U=Q^2/(2C) decreases.

  • Battery-connected capacitor: Its potential difference ΔV\Delta V stays constant. As CC increases, the capacitor draws more charge, and its stored energy U=12C(ΔV)2U=\frac{1}{2}C(\Delta V)^2 increases.

Always identify what is held constant before comparing charge, potential difference, or energy. Energy can be exchanged with the battery or through mechanical forces as the enters the gap.

Takeaway: Inserting a increases , but the changes to charge, potential difference, and energy depend on whether charge or is held constant.