1 Electrical Quantities and Ohm’s Law

Learn how charge, current, voltage, resistance, power, and energy are related in electric circuits, including how to apply Ohm’s law and interpret worked calculations.

Charge and current

Electric circuits involve the movement of and the transfer of . The quantities used to describe circuits indicate how much charge moves, how strongly it is driven, how much a material opposes its motion, and how quickly is transferred.

is a property of matter, measured in coulombs (C\text{C}) and often represented by QQ or qq. The magnitude of the charge of one electron is approximately 1.602×10−19 C1.602 \times 10^{-19}\,\text{C}.

is the rate at which charge passes a point:

I=QtI = \frac{Q}{t}

Here, II is current in amperes (A\text{A}), QQ is charge in coulombs, and tt is time in seconds. Since 1 A=1 C/s1\,\text{A} = 1\,\text{C/s}, a current of 2 A2\,\text{A} carries 2 C2\,\text{C} of charge past a point each second. Rearranging the current equation gives Q=ItQ = It.

and potential difference

, or potential difference, describes the transferred per unit of charge between two points:

V=EQV = \frac{E}{Q}

is measured in volts (V\text{V}), where 1 V=1 J/C1\,\text{V} = 1\,\text{J/C}. A 9 V9\,\text{V} source can transfer 9 J9\,\text{J} of for each coulomb of charge that passes through it. is always measured between two points.

and

describes how strongly a component opposes current. It is measured in ohms (Ω\Omega), with 1 Ω=1 V/A1\,\Omega = 1\,\text{V/A}.

For many resistors under steady conditions, , current, and are related by :

V=IRV = IR

The relationship can be rearranged to find current or :

I=VR,R=VII = \frac{V}{R}, \qquad R = \frac{V}{I}

For a fixed , increasing increases current. For a fixed , increasing decreases current. describes ohmic components, for which is proportional to current under the conditions considered; not every component has this proportional relationship.

For example, a 6 Ω6\,\Omega resistor connected across a 12 V12\,\text{V} source carries a current of:

I=VR=12 V6 Ω=2 AI = \frac{V}{R} = \frac{12\,\text{V}}{6\,\Omega} = 2\,\text{A}

Power and

is the rate of transfer. It is measured in watts (W\text{W}), where 1 W=1 J/s1\,\text{W} = 1\,\text{J/s}. For a circuit element:

P=VIP = VI

For an ohmic resistor, substituting gives two further forms:

P=I2R,P=V2RP = I^2R, \qquad P = \frac{V^2}{R}

transferred over a time interval is power multiplied by time:

E=PtE = Pt

is measured in joules (J\text{J}). Household electricity use is often stated in kilowatt-hours (kWh\text{kWh}), with 1 kWh=3.6×106 J1\,\text{kWh} = 3.6 \times 10^6\,\text{J}.

For the 6 Ω6\,\Omega resistor connected to a 12 V12\,\text{V} source, the current is 2 A2\,\text{A}, so its power is:

P=VI=(12 V)(2 A)=24 WP = VI = (12\,\text{V})(2\,\text{A}) = 24\,\text{W}

If it operates for 55 minutes, or 300 s300\,\text{s}, the transferred is:

E=Pt=(24 W)(300 s)=7200 JE = Pt = (24\,\text{W})(300\,\text{s}) = 7200\,\text{J}

The charge passing through it during that time is:

Q=It=(2 A)(300 s)=600 CQ = It = (2\,\text{A})(300\,\text{s}) = 600\,\text{C}

Checking the using and charge gives VQ=(12 V)(600 C)=7200 JVQ = (12\,\text{V})(600\,\text{C}) = 7200\,\text{J}, consistent with the calculation using power and time.