6 Gases and the Gas Laws

Learn how pressure, volume, temperature, and amount of gas are related, then apply gas laws to individual gases and mixtures.

and gas-state variables

Gas particles move constantly and collide with the walls of their container. The collisions exert force over an area, producing . In equation form, is P=FAP = \frac{F}{A}, where FF is force and AA is area.

A gas sample is described by PP, volume VV, temperature TT, and amount nn, measured in moles. units include pascals (Pa\mathrm{Pa}), kilopascals (kPa\mathrm{kPa}), atmospheres (atm\mathrm{atm}), and torr. A useful conversion is

1 atm=101.325 kPa=760 torr.1\ \mathrm{atm} = 101.325\ \mathrm{kPa} = 760\ \mathrm{torr}.

Gas-law temperature calculations use the , not Celsius degrees:

T(K)=T(∘C)+273.15.T(\mathrm{K}) = T(\mathrm{^\circ C}) + 273.15.

Use a consistent set of units, including a gas constant that matches the and volume units.

Simple gas laws

Simple gas laws describe how two gas variables change while the other relevant variables are held constant. The conditions matter: a relationship applies only when its stated quantities remain fixed.

  • : At constant temperature and amount of gas, and volume vary inversely: P1V1=P2V2P_1V_1 = P_2V_2. Compressing a gas at constant temperature therefore raises its .

  • Charles’s law: At constant and amount of gas, volume is proportional to absolute temperature: V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}. A balloon can expand as its gas warms if the external remains approximately constant.

  • Amontons’s (Gay-Lussac’s) law: At constant volume and amount of gas, is proportional to absolute temperature: P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2}.

  • Avogadro’s law: At constant and temperature, volume is proportional to the amount of gas: V1n1=V2n2\frac{V_1}{n_1} = \frac{V_2}{n_2}.

Always use kelvins in relationships involving temperature. For example, a gas occupies 2.0 L2.0\ \mathrm{L} at 300 K300\ \mathrm{K}. If it warms to 450 K450\ \mathrm{K} at constant , Charles’s law gives

V2=2.0 L×450 K300 K=3.0 L.V_2 = 2.0\ \mathrm{L} \times \frac{450\ \mathrm{K}}{300\ \mathrm{K}} = 3.0\ \mathrm{L}.

Takeaway: Identify which quantities are constant before choosing a simple gas law.

Combining gas variables

When the amount of gas is fixed but , volume, and temperature can all change, combine the pairwise relationships into the combined gas law:

P1V1T1=P2V2T2.\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}.

For a broader relationship that includes the amount of gas, use the :

PV=nRT.PV = nRT.

The ideal gas constant RR has several possible values. Two common choices are 0.08206 L⋅atm⋅mol−1⋅K−10.08206\ \mathrm{L\cdot atm\cdot mol^{-1}\cdot K^{-1}} and 8.314 kPa⋅L⋅mol−1⋅K−18.314\ \mathrm{kPa\cdot L\cdot mol^{-1}\cdot K^{-1}}. Choose the value that matches the and volume units in the calculation. The ideal-gas model is a useful approximation for many gases, especially at relatively low and high temperature.

Example: Find the volume of 0.500 mol0.500\ \mathrm{mol} of gas at 298 K298\ \mathrm{K} and 1.00 atm1.00\ \mathrm{atm}, using R=0.08206 L⋅atm⋅mol−1⋅K−1R = 0.08206\ \mathrm{L\cdot atm\cdot mol^{-1}\cdot K^{-1}}:

V=nRTP=(0.500 mol)(0.08206 L⋅atm⋅mol−1⋅K−1)(298 K)1.00 atm=12.2 L.V = \frac{nRT}{P} = \frac{(0.500\ \mathrm{mol})(0.08206\ \mathrm{L\cdot atm\cdot mol^{-1}\cdot K^{-1}})(298\ \mathrm{K})}{1.00\ \mathrm{atm}} = 12.2\ \mathrm{L}.

Takeaway: Use the combined gas law when the amount is fixed; use the when the amount is part of the problem.

Partial pressures in gas mixtures

For a mixture of gases that do not react, states that the total is the sum of the pressures each component would exert on its own in the same container:

Ptotal=P1+P2+⋯=∑iPi.P_{\mathrm{total}} = P_1 + P_2 + \cdots = \sum_i P_i.

A component’s , XiX_i, is the fraction of the mixture’s total gas amount contributed by that component. Its partial is found from

Xi=nintotal,Pi=XiPtotal.X_i = \frac{n_i}{n_{\mathrm{total}}}, \qquad P_i = X_iP_{\mathrm{total}}.

For example, a mixture containing 25%25\% nitrogen and 75%75\% oxygen by moles has a total of 2.0 atm2.0\ \mathrm{atm}. The nitrogen partial is 0.25×2.0 atm=0.50 atm0.25 \times 2.0\ \mathrm{atm} = 0.50\ \mathrm{atm}, and the oxygen partial is 0.75×2.0 atm=1.5 atm0.75 \times 2.0\ \mathrm{atm} = 1.5\ \mathrm{atm}. Their sum is the total .

When a gas is collected over water, the sample includes water vapor as well as the gas of interest. The total is the sum of the dry gas and the water vapor , so

Pdry gas=Ptotal−Pwater vapor.P_{\mathrm{dry\ gas}} = P_{\mathrm{total}} - P_{\mathrm{water\ vapor}}.

Takeaway: For a gas mixture, add component partial pressures to find the total; subtract water vapor when determining the of a dry gas collected over water.