Free Online Flashcard Deck

06 Fundamental Counting Principles Free Online FlashCards

Study 06 Fundamental Counting Principles with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

When does the addition principle apply?

Back

Add the counts of mutually exclusive cases. If one case has aa outcomes and another has bb, the total is a+ba+b.

02
Front

When does the multiplication principle apply?

Back

Multiply the numbers of choices at each stage. For stages with a1,a2,…,aka_1,a_2,\ldots,a_k choices, the total is a1a2⋯aka_1a_2\cdots a_k.

03
Front

What is the definition of n!n!?

Back

For a nonnegative integer nn, n!=n(n−1)⋯2⋅1n!=n(n-1)\cdots2\cdot1, and 0!=10!=1.

04
Front

What formula counts ordered selections of rr from nn?

Back

The number of ordered selections of rr distinct objects from nn is P(n,r)=n!(n−r)!P(n,r)=\frac{n!}{(n-r)!}.

05
Front

How are arrangements with identical repeated objects counted?

Back

Distinct arrangements of repeated objects are counted by dividing n!n! by the factorial of each repetition count: n!r1!r2!⋯rk!\frac{n!}{r_1!r_2!\cdots r_k!}.

06
Front

What formula counts unordered selections?

Back

A combination is an unordered selection. The number of ways to choose rr objects from nn is (nr)=n!r!(n−r)!\binom{n}{r}=\frac{n!}{r!(n-r)!}.

07
Front

How are permutations and combinations related?

Back

Each combination of rr objects has r!r! orderings, so P(n,r)=(nr)r!P(n,r)=\binom{n}{r}r!.

08
Front

What does the pigeonhole principle guarantee?

Back

If more than mm objects are placed into mm boxes, at least one box contains at least two objects.

09
Front

What is the generalized pigeonhole bound?

Back

If nn objects are distributed among mm boxes, some box contains at least ⌈nm⌉\left\lceil\frac{n}{m}\right\rceil objects.

10
Front

How many 5-digit codes meet the stated no-repeat restriction?

Back

There are 9⋅9⋅8⋅7⋅6=27,2169\cdot9\cdot8\cdot7\cdot6=27{,}216 such codes: 9 choices for the first digit, then 9, 8, 7, and 6.

11
Front

How many 4-person committees exclude a particular pair together?

Back

Count all committees and subtract those containing both people: (104)−(82)=210−28=182\binom{10}{4}-\binom{8}{2}=210-28=182.

12
Front

How many arrangements keep A and B adjacent?

Back

Treat A and B as one block: 4!4! arrangements of the block with C, D, and E, times 2!2! internal orders. The total is 4!⋅2!=484!\cdot2!=48.