Free Online Flashcard Deck

06 Multiple Integrals in Curvilinear Coordinates Free Online FlashCards

Study 06 Multiple Integrals in Curvilinear Coordinates with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What does a Jacobian measure?

Back

The Jacobian is the local area-scaling factor of a two-dimensional transformation, or the local volume-scaling factor in three dimensions.

02
Front

What are the three steps in a coordinate change?

Back

Rewrite the integrand, transform the region and bounds, and replace the area or volume element with the absolute Jacobian.

03
Front

What are the Cartesian-to-polar formulas?

Back

The polar conversion formulas are x=rcos⁡θx=r\cos\theta and y=rsin⁡θy=r\sin\theta, where rr is distance from the origin.

04
Front

What is the polar area element?

Back

The planar area element is dA=r dr dθdA=r\,dr\,d\theta. The factor rr comes from the polar Jacobian.

05
Front

What are polar bounds for x2+y2≤a2x^2+y^2\le a^2?

Back

Use 0≤r≤a0\le r\le a and 0≤θ≤2π0\le\theta\le2\pi. These bounds cover the entire disk exactly once.

06
Front

How do cylindrical coordinates extend polar coordinates?

Back

Cylindrical coordinates use x=rcos⁡θx=r\cos\theta, y=rsin⁡θy=r\sin\theta, and leave zz unchanged.

07
Front

What is the cylindrical volume element?

Back

The cylindrical volume element is dV=r dr dθ dzdV=r\,dr\,d\theta\,dz. Its Jacobian is rr.

08
Front

How are spherical angles defined?

Back

In the standard convention, θ\theta is the azimuthal angle in the xyxy-plane, while ϕ\phi is measured downward from the positive zz-axis.

09
Front

What are the Cartesian-to-spherical formulas?

Back

The spherical conversion is x=ρsin⁡ϕcos⁡θx=\rho\sin\phi\cos\theta, y=ρsin⁡ϕsin⁡θy=\rho\sin\phi\sin\theta, and z=ρcos⁡ϕz=\rho\cos\phi.

10
Front

What is the spherical volume element?

Back

The spherical volume element is dV=ρ2sin⁡ϕ dρ dϕ dθdV=\rho^2\sin\phi\,d\rho\,d\phi\,d\theta.

11
Front

Which spherical angle describes z=x2+y2z=\sqrt{x^2+y^2}?

Back

The cone z=x2+y2z=\sqrt{x^2+y^2} becomes ϕ=π4\phi=\frac{\pi}{4}.

12
Front

What are cylindrical bounds for the upper hemisphere?

Back

For the upper hemisphere, use 0≤r≤R0\le r\le R, 0≤θ≤2π0\le\theta\le2\pi, and 0≤z≤R2−r20\le z\le\sqrt{R^2-r^2}.