Why do parametrized surfaces generally use two parameters?
A surface is two-dimensional, so its points generally require two parameters, such as and , in a vector-valued parametrization .
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Why do parametrized surfaces generally use two parameters?
A surface is two-dimensional, so its points generally require two parameters, such as u and v, in a vector-valued parametrization r(u,v).
What is the parameter domain?
The parameter domain is the region D in the uv-plane over which the parameters vary to generate the surface.
How are coordinate curves obtained from r(u,v)?
Holding u constant and varying v gives one family of coordinate curves; holding v constant and varying u gives the other.
What condition makes a parametrization regular?
The parametrization is regular at a point when ru×rv=0. Then the tangent directions are not parallel and determine a tangent plane.
How is the tangent plane found from a parametrization?
At P=r(u0,v0), a tangent-plane equation is (ru×rv)∣(u0,v0)⋅⟨x−x0,y−y0,z−z0⟩=0.
What are the two unit normals to an oriented parametrized surface?
The two unit normals are N=±∥ru×rv∥ru×rv. Choosing the sign fixes the surface orientation.
How is the graph z=f(x,y) parametrized?
A graph z=f(x,y) can be parametrized by r(x,y)=⟨x,y,f(x,y)⟩ over its region D.
What is the surface-area element for a parametrized surface?
For r(u,v), the surface-area element is dS=∥ru×rv∥dudv.
What is the area formula for a graph?
For z=f(x,y), dS=1+fx2+fy2dA, so Area(S)=∬D1+fx2+fy2dA.
How is a scalar surface integral computed parametrically?
A scalar surface integral is ∬SgdS=∬Dg(r(u,v))∥ru×rv∥dudv.
What physical quantities can a scalar surface integral represent?
If g is surface density, then ∬SgdS gives total mass. If g=1, it gives the surface area.
What is the parametrized formula for flux?
The flux is ∬SF⋅NdS=∬DF(r(u,v))⋅(ru×rv)dudv.