Free Online Flashcard Deck

3 Rates of Change and Derivatives Free Online FlashCards

Study 3 Rates of Change and Derivatives with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What is the average rate of change from x=ax=a to x=bx=b?

Back

The average rate of change is f(b)−f(a)b−a\frac{f(b)-f(a)}{b-a}, representing output change divided by input change over an interval.

02
Front

What does an instantaneous rate of change represent?

Back

It is the slope of the tangent line to the graph at that point, describing how the quantity changes at one particular input value.

03
Front

State the limit definition of f′(a)f'(a).

Back

The derivative at aa is f′(a)=lim⁡h→0f(a+h)−f(a)hf'(a)=\lim_{h\to0}\frac{f(a+h)-f(a)}{h}, when this limit exists.

04
Front

Why is hh not set equal to zero in the derivative quotient?

Back

The quotient cannot be evaluated at h=0h=0 because it would require division by zero. The limit instead examines values as nonzero hh gets arbitrarily close to zero.

05
Front

Using the definition, what is the derivative of f(x)=x2f(x)=x^2?

Back

For f(x)=x2f(x)=x^2, the definition gives f′(x)=2xf'(x)=2x. Therefore, f′(3)=6f'(3)=6.

06
Front

How are the units of a derivative determined?

Back

The derivative has units of output divided by input: units of f′=units of funits of x\text{units of }f'=\frac{\text{units of }f}{\text{units of }x}.

07
Front

How are velocity and acceleration related to position?

Back

If s(t)s(t) is position, then instantaneous velocity is v(t)=s′(t)v(t)=s'(t), and instantaneous acceleration is a(t)=s′′(t)a(t)=s''(t).

08
Front

Find v(2)v(2) and a(2)a(2) for s(t)=t2+3ts(t)=t^2+3t.

Back

For s(t)=t2+3ts(t)=t^2+3t, v(t)=2t+3v(t)=2t+3 and a(t)=2a(t)=2. Thus, at t=2t=2, velocity is 7 m/s7\text{ m/s} and acceleration is 2 m/s22\text{ m/s}^2.

09
Front

What is the power rule?

Back

The power rule is ddx(xn)=nxn−1\frac{d}{dx}(x^n)=nx^{n-1} for a real number nn.

10
Front

What is the derivative of a constant?

Back

The derivative of a constant is zero: if f(x)=Cf(x)=C, then f′(x)=0f'(x)=0.

11
Front

How do sum and difference rules simplify differentiation?

Back

Differentiate each term separately. For f(x)=3x4−5x2+7f(x)=3x^4-5x^2+7, the derivative is f′(x)=12x3−10xf'(x)=12x^3-10x.

12
Front

How do velocity and acceleration indicate speeding up or slowing down?

Back

An object speeds up when velocity and acceleration have the same sign; it slows down when they have opposite signs.