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6 Linear Transformations Free Online FlashCards

Study 6 Linear Transformations with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What condition defines a linear transformation?

Back

A linear transformation preserves linear combinations: for scalars a,ba,b, T(au+bv)=aT(u)+bT(v)T(a\mathbf{u}+b\mathbf{v})=aT(\mathbf{u})+bT(\mathbf{v}).

02
Front

What must a linear transformation do to the zero vector?

Back

Every linear transformation maps the zero vector to the zero vector: T(0)=0T(\mathbf{0})=\mathbf{0}.

03
Front

Why does a basis determine a linear transformation?

Back

A linear transformation is completely determined by its values on a basis, because every vector is a linear combination of the basis vectors.

04
Front

What is the kernel of a linear transformation?

Back

The kernel is ker⁡T={v:T(v)=0}\ker T=\{\mathbf{v}:T(\mathbf{v})=\mathbf{0}\}, the set of inputs sent to the zero vector.

05
Front

What is the image of a linear transformation?

Back

The image is im⁡T={T(v):v∈V}\operatorname{im}T=\{T(\mathbf{v}):\mathbf{v}\in V\}, the set of all attainable outputs.

06
Front

How is a matrix transformation’s kernel found?

Back

For a matrix transformation TA(x)=AxT_A(\mathbf{x})=A\mathbf{x}, the kernel is the null space {x:Ax=0}\{\mathbf{x}:A\mathbf{x}=\mathbf{0}\}.

07
Front

What is the image of a matrix transformation?

Back

For TA(x)=AxT_A(\mathbf{x})=A\mathbf{x}, the image is the column space of AA, spanned by the columns of AA.

08
Front

When is a linear transformation injective?

Back

A linear transformation is injective exactly when its kernel is trivial: ker⁡T={0}\ker T=\{\mathbf{0}\}.

09
Front

When is a linear transformation surjective?

Back

A linear transformation is surjective exactly when its image equals the entire codomain: im⁡T=W\operatorname{im}T=W.

10
Front

What does each column of a relative matrix representation contain?

Back

The matrix [T]C←B[T]_{\mathcal{C}\leftarrow\mathcal{B}} has column jj equal to [T(vj)]C[T(\mathbf{v}_j)]_{\mathcal{C}}.

11
Front

What matrix represents a composition of transformations?

Back

If AA represents UU and BB represents TT, then [T∘U]=BA[T\circ U]=BA: apply AA first, then BB.

12
Front

What does a change-of-coordinate matrix do?

Back

If P=PB←B′P=P_{\mathcal{B}\leftarrow\mathcal{B}'}, then [v]B=P[v]B′[\mathbf{v}]_{\mathcal{B}}=P[\mathbf{v}]_{\mathcal{B}'}. Its columns contain the new basis vectors in old coordinates.