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6 The Fundamental Theorem of Calculus Free Online FlashCards

Study 6 The Fundamental Theorem of Calculus with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What is an antiderivative of ff?

Back

An antiderivative of f is a function F satisfying F′(x)=f(x)F'(x)=f(x).

02
Front

What does the constant CC represent in an indefinite integral?

Back

An indefinite integral represents a family of antiderivatives and includes an arbitrary constant: ∫f(x) dx=F(x)+C\int f(x)\,dx=F(x)+C.

03
Front

What does a definite integral measure?

Back

A definite integral measures signed accumulation, or net area: contributions above the axis are positive and those below it are negative.

04
Front

What does FTC Part 1 say about G(x)=∫axf(t) dtG(x)=\int_a^x f(t)\,dt?

Back

If G(x)=∫axf(t) dtG(x)=\int_a^x f(t)\,dt and f is continuous, then G′(x)=f(x)G'(x)=f(x).

05
Front

Why is tt called a dummy variable in ∫axf(t) dt\int_a^x f(t)\,dt?

Back

The dummy variable t distinguishes the integration variable from the variable upper limit x; it can be replaced by another variable without changing the integral.

06
Front

State FTC Part 2.

Back

For continuous f with antiderivative F, ∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx=F(b)-F(a).

07
Front

Evaluate ∫13(2x3−4x+1) dx\int_1^3(2x^3-4x+1)\,dx.

Back

An antiderivative is F(x)=x42−2x2+xF(x)=\frac{x^4}{2}-2x^2+x, so F(3)−F(1)=24F(3)-F(1)=24.

08
Front

Should you include +C+C when evaluating a definite integral?

Back

No. In a definite integral, the constants cancel: (F(b)+C)−(F(a)+C)=F(b)−F(a)(F(b)+C)-(F(a)+C)=F(b)-F(a).

09
Front

What does the Net Change Theorem state?

Back

The net change equals the integral of the rate: Q(b)−Q(a)=∫abQ′(t) dtQ(b)-Q(a)=\int_a^b Q'(t)\,dt.

10
Front

Find the displacement when v(t)=3t2−4tv(t)=3t^2-4t from t=1t=1 to t=3t=3.

Back

The displacement is ∫13(3t2−4t) dt=10 m\int_1^3(3t^2-4t)\,dt=10\text{ m}.

11
Front

How does total distance differ from displacement?

Back

Total distance uses speed: ∫ab∣v(t)∣ dt\int_a^b|v(t)|\,dt, or it splits the interval wherever velocity changes sign.

12
Front

For f(x)=x−1f(x)=x-1 on [0,2][0,2], what is the total geometric area?

Back

The net area is 00, but the total geometric area is ∫01(1−x) dx+∫12(x−1) dx=1\int_0^1(1-x)\,dx+\int_1^2(x-1)\,dx=1.