Which statement best explains what means?
2 Limits and Continuity Online Quiz Questions
Use this free practice quiz with 20 questions to review 2 Limits and Continuity, test your knowledge, and prepare for your next test or exam.
Evaluate limx→∞x2−32x2+1.
- A
0
- B
1
- C
2
- D
The limit does not exist because both degrees are equal.
Which set of conditions is required for a function to be continuous at x=a?
- A
Only f(a) must be defined.
- B
The left- and right-hand limits may differ as long as f(a) is defined.
- C
The limit must exist, but it need not equal f(a).
- D
All three conditions must hold: f(a) is defined, the limit exists, and the limit equals f(a).
Select all conditions that are sufficient for the two-sided limit limx→af(x) to exist.
- A
The left-hand and right-hand limits are equal.
- B
The function must be defined at a.
- C
Both one-sided limits exist.
- D
The graph must contain the point (a,L).
Select all algebraic techniques identified in the material as useful for evaluating indeterminate limits of suitable expressions.
- A
Factoring and canceling common factors can help.
- B
Substituting the target value repeatedly always gives an exact result.
- C
Multiplying every expression by its denominator is a valid general method.
- D
Multiplying by a conjugate can help with expressions involving radicals.
A function can have a removable discontinuity at x=a even if its two-sided limit exists.
- A
True
- B
False
Because limx→0+x1=∞ and limx→0−x1=−∞, the two-sided limit limx→0x1 exists as an infinite limit.
- A
True
- B
False
Find the exact value of limx→2x−2x2−4.
A graph approaches y=3 from both sides as x→4, but the point at x=4 is missing. The limit is limx→4f(x)=.
For f(x)={x2,2x−1,x<1x≥1, the function is at x=1.
Use the Intermediate Value Property to explain why the function f(x)=x3−x−1 has at least one zero in the interval (1,2).
Find the exact value of limx→3(2x2−x+4).
For f(x)=x−1x2−1, which statement correctly describes the behavior as x→1?
- A
The limit does not exist because the original function is undefined at x=1.
- B
The limit is 2, and the graph has a removable discontinuity at (1,2).
- C
The limit is 1, because the denominator approaches zero.
- D
The limit is infinite, and x=1 is a vertical asymptote.
Evaluate x→3lim(2x2−x+4).
- A
17
- B
19
- C
21
- D
25
True or false: A two-sided limit can exist even if the function is undefined at the value being approached.
- A
True
- B
False
Evaluate x→2limx−2x2−4.
- A
0
- B
2
- C
4
- D
Does not exist
For f(x)={x+1,5−x,x<2,x≥2, evaluate x→2limf(x).
- A
2
- B
3
- C
4
- D
The limit does not exist
Evaluate x→0limxx+1−1.
- A
21
- B
1
- C
2
- D
0
What type of discontinuity does f(x)=x−11 have at x=1?
Find the exact value of x→0limx1+2x−1. Enter the answer as a number; the absolute tolerance is 0.