Free Practice Quiz Question List

02 The Mole and Chemical Composition Online Quiz Questions

Use this free practice quiz with 30 questions to review 02 The Mole and Chemical Composition, test your knowledge, and prepare for your next test or exam.

30 questions
01
Open ended
1 point

Using 12.01 g/mol12.01\ \mathrm{g/mol} for carbon and 1.008 g/mol1.008\ \mathrm{g/mol} for hydrogen, calculate the molar mass of methane, CH4\mathrm{CH_4}, and the mass percentage of each element. Show the mass contribution used for each percentage and check that the percentages total approximately 100%100\%.

02
Open ended
1 point

A 29.22 g29.22\ \mathrm{g} sample of NaCl has a molar mass of 58.44 g/mol58.44\ \mathrm{g/mol}. Determine the amount of NaCl in moles and the number of NaCl formula units in the sample. Use 6.02214076×10236.02214076\times10^{23} entities per mole, and report the entity type explicitly.

03
Open ended
1 point

A sample contains 0.125 mol0.125\ \mathrm{mol} of H2O\mathrm{H_2O}. Use 6.02214076×10236.02214076\times10^{23} entities per mole to determine the number of water molecules, hydrogen atoms, and oxygen atoms. Report each count to three significant figures and label what is being counted.

04
Open ended
1 point

A compound contains 24.02 g24.02\ \mathrm{g} C, 3.024 g3.024\ \mathrm{g} H, and 16.00 g16.00\ \mathrm{g} O. Using molar masses of 12.0112.01, 1.0081.008, and 16.00 g/mol16.00\ \mathrm{g/mol}, respectively, determine the empirical formula. Show the mole ratio and how you reduce it.

05
Open ended
1 point

A compound is 52.2%52.2\% C, 13.0%13.0\% H, and 34.8%34.8\% O by mass. Using molar masses of 12.0112.01, 1.0081.008, and 16.00 g/mol16.00\ \mathrm{g/mol}, respectively, determine its empirical formula. Show how you convert the mass percentages to a simplest whole-number atom ratio.

06
Open ended
1 point

After converting a compound’s elemental masses to moles and dividing by the smallest amount, you obtain C:H:O=1.00:1.48:1.00\mathrm{C:H:O}=1.00:1.48:1.00. Determine the most reasonable empirical formula and explain why simply rounding 1.481.48 to 11 would be a poor choice.

07
Open ended
1 point

An oxide is 27.3%27.3\% C and 72.7%72.7\% O by mass. Using molar masses of 12.01 g/mol12.01\ \mathrm{g/mol} for C and 16.00 g/mol16.00\ \mathrm{g/mol} for O, determine its empirical formula. Explain why the two percentages themselves cannot be used directly as the atom ratio.

08
Open ended
1 point

A compound has empirical formula C2H3O\mathrm{C_2H_3O} and molecular molar mass 129.13 g/mol129.13\ \mathrm{g/mol}. Using 12.0112.01, 1.0081.008, and 16.00 g/mol16.00\ \mathrm{g/mol} for C, H, and O, respectively, determine its molecular formula. Show the empirical-formula mass and multiplier.

09
Open ended
1 point

Two compounds share the empirical formula C2H3O\mathrm{C_2H_3O}, but their molecular molar masses are 86.09 g/mol86.09\ \mathrm{g/mol} and 129.13 g/mol129.13\ \mathrm{g/mol}. Using atomic molar masses C =12.01=12.01, H =1.008=1.008, and O =16.00 g/mol=16.00\ \mathrm{g/mol}, determine the molecular formula for each compound and explain what this comparison shows about empirical formulas.

10
Open ended
1 point

A sample is reported to have empirical formula C2H3O\mathrm{C_2H_3O} and molecular molar mass 77.0 g/mol77.0\ \mathrm{g/mol}. Using C =12.01=12.01, H =1.008=1.008, and O =16.00 g/mol=16.00\ \mathrm{g/mol}, assess whether these data can yield a valid molecular formula. Show the calculation and state the appropriate conclusion.

11
Open ended
1 point

An unknown compound has empirical formula C3H4O\mathrm{C_3H_4O} and molecular molar mass 168.19 g/mol168.19\ \mathrm{g/mol}. Use atomic molar masses C =12.01=12.01, H =1.008=1.008, and O =16.00 g/mol=16.00\ \mathrm{g/mol} to determine the molecular formula. Show the empirical-formula mass and demonstrate that the result is a whole-number multiple of the empirical formula.

12
Open ended
1 point

Calcium hydroxide has formula Ca(OH)2\mathrm{Ca(OH)_2}. Using atomic molar masses of 40.08 g/mol40.08\ \mathrm{g/mol} for Ca, 16.00 g/mol16.00\ \mathrm{g/mol} for O, and 1.008 g/mol1.008\ \mathrm{g/mol} for H, calculate the mass of a 3.203.20-mol sample. Report your result to three significant figures.

13
Open ended
1 point

A KBr sample has a mass of 11.90 g11.90\ \mathrm{g}, and its molar mass is 119.00 g/mol119.00\ \mathrm{g/mol}. How many KBr formula units does the sample contain? Use NA=6.02214076×1023 entities/molN_A = 6.02214076 \times 10^{23}\ \mathrm{entities/mol}, and report your result to four significant figures.

14
Open ended
1 point

For 0.250 mol0.250\ \mathrm{mol} of Al2(SO4)3\mathrm{Al_2(SO_4)_3} formula units, determine the amount in moles of Al atoms, S atoms, and O atoms separately, then find the total amount of atoms.

15
Open ended
1 point

Calculate the mass percent of each element in Na2SO4\mathrm{Na_2SO_4}. Use atomic molar masses of 22.99 g/mol22.99\ \mathrm{g/mol} for Na, 32.06 g/mol32.06\ \mathrm{g/mol} for S, and 16.00 g/mol16.00\ \mathrm{g/mol} for O. Show the molar mass and the three percentages.

16
Open ended
1 point

A compound is 27.3%27.3\% carbon and 72.7%72.7\% oxygen by mass. Using atomic molar masses of 12.01 g/mol12.01\ \mathrm{g/mol} for C and 16.00 g/mol16.00\ \mathrm{g/mol} for O, determine its empirical formula. Show how you obtain the simplest whole-number ratio.

17
Open ended
1 point

A sample contains 6.01 g6.01\ \mathrm{g} C, 0.756 g0.756\ \mathrm{g} H, and 8.00 g8.00\ \mathrm{g} O. Using atomic molar masses of 12.01 g/mol12.01\ \mathrm{g/mol} for C, 1.008 g/mol1.008\ \mathrm{g/mol} for H, and 16.00 g/mol16.00\ \mathrm{g/mol} for O, determine the empirical formula. Show how you handle any non-whole-number ratio.

18
Open ended
1 point

A compound has empirical formula CH2\mathrm{CH_2} and molecular molar mass 84.16 g/mol84.16\ \mathrm{g/mol}. Using atomic molar masses of 12.01 g/mol12.01\ \mathrm{g/mol} for C and 1.008 g/mol1.008\ \mathrm{g/mol} for H, determine its molecular formula. Show the multiplier.

19
Open ended
1 point

A compound has empirical formula C2H6O\mathrm{C_2H_6O} and molecular molar mass 92.14 g/mol92.14\ \mathrm{g/mol}. Using atomic molar masses of 12.01 g/mol12.01\ \mathrm{g/mol} for C, 1.008 g/mol1.008\ \mathrm{g/mol} for H, and 16.00 g/mol16.00\ \mathrm{g/mol} for O, determine its molecular formula and explain how each subscript changes.

20
Open ended
1 point

A compound is 30.45%30.45\% N and 69.55%69.55\% O by mass, and its molecular molar mass is 92.02 g/mol92.02\ \mathrm{g/mol}. Using atomic molar masses of 14.01 g/mol14.01\ \mathrm{g/mol} for N and 16.00 g/mol16.00\ \mathrm{g/mol} for O, determine both its empirical formula and its molecular formula. Show the calculation that links the two.

21
Open ended
1 point

Explain why an empirical formula alone cannot determine a compound's molecular formula. Give two different molecular formulas with the same empirical formula, and identify what additional information can determine the multiplier.

22
Open ended
1 point

A compound is reported to have an empirical-formula mass of 30.03 g/mol30.03\ \mathrm{g/mol} and a molecular molar mass of 75.0 g/mol75.0\ \mathrm{g/mol}. Calculate the implied multiplier and assess whether these values support a molecular formula under the whole-number-multiple rule. Explain what should be done rather than rounding the multiplier without justification.

23
Open ended
1 point

An analysis reports mass percentages of 24.7%24.7\%, 18.6%18.6\%, and 56.5%56.5\% for the elements in a compound. Find their total and explain whether the result, by itself, means the composition is invalid.

24
Open ended
1 point

A sample contains 0.250 mol0.250\ \mathrm{mol} of H2O\mathrm{H_2O}. Calculate the number of water molecules, hydrogen atoms, and oxygen atoms in the sample. Report entity counts to three significant figures, and identify what each count refers to.

25
Open ended
1 point

A laboratory compares 1.25 mol1.25\ \mathrm{mol} samples of NaCl and H2O\mathrm{H_2O}. Using molar masses of 58.44 g/mol58.44\ \mathrm{g/mol} for NaCl and 18.02 g/mol18.02\ \mathrm{g/mol} for H2O\mathrm{H_2O}, calculate each sample's mass to three significant figures. Explain why equal amounts in moles do not have equal masses.

26
Open ended
1 point

Using atomic molar masses C=12.01\mathrm{C}=12.01, H=1.008\mathrm{H}=1.008, and O=16.00 g/mol\mathrm{O}=16.00\ \mathrm{g/mol}, calculate the mass percent of each element in C2H6O\mathrm{C_2H_6O}. Show how you obtain the molar mass and each element's contribution, and check the total percentage.

27
Open ended
1 point

A sample contains 24.02 g24.02\ \mathrm{g} of carbon, 3.024 g3.024\ \mathrm{g} of hydrogen, and 32.00 g32.00\ \mathrm{g} of oxygen. Using atomic molar masses C=12.01\mathrm{C}=12.01, H=1.008\mathrm{H}=1.008, and O=16.00 g/mol\mathrm{O}=16.00\ \mathrm{g/mol}, determine the empirical formula. Show the mole ratio and how you reduce it.

28
Open ended
1 point

A compound has empirical formula CH2O\mathrm{CH_2O} and molecular molar mass 180.16 g/mol180.16\ \mathrm{g/mol}. Using atomic molar masses C=12.01\mathrm{C}=12.01, H=1.008\mathrm{H}=1.008, and O=16.00 g/mol\mathrm{O}=16.00\ \mathrm{g/mol}, determine its molecular formula. Show the empirical-formula mass, the multiplier, and how the subscripts change.

29
Open ended
1 point

Experimental mole amounts for carbon, hydrogen, and oxygen produce the ratio 1.00:1.50:2.001.00:1.50:2.00. Determine the simplest whole-number ratio and corresponding empirical formula. Explain why rounding 1.501.50 to the nearest whole number before reducing the ratio would be a poor choice.

30
Open ended
1 point

Ethanol is written as C2H5OH\mathrm{C_2H_5OH}. Using 12.01 g/mol12.01\ \mathrm{g/mol} for carbon, 1.008 g/mol1.008\ \mathrm{g/mol} for hydrogen, and 16.00 g/mol16.00\ \mathrm{g/mol} for oxygen, calculate its molar mass. Show the sum of the atomic contributions and explain how many hydrogen atoms are included in that sum.