A block is at rest on a rough surface, and its contact with the surface is not at impending slip. Is its static friction force necessarily equal to ?
8 Friction and Mechanical Applications Online Quiz Questions
Use this free practice quiz with 20 questions to review 8 Friction and Mechanical Applications, test your knowledge, and prepare for your next test or exam.
A body slides across a rough horizontal surface. Which statement describes the friction force in the simplified Coulomb model?
- A
It adjusts from zero up to μsN.
- B
It is modeled as Fk=μkN.
- C
It is always equal to μsN.
- D
It acts perpendicular to the contacting surfaces.
Which statements about dry friction are correct? Select all that apply.
- A
Friction can point in the same direction as a body's overall motion.
- B
Friction always points opposite the body's overall motion.
- C
The coefficients of friction are dimensionless.
- D
Static friction must equal its limiting value whenever a body is at rest.
At impending slip, the magnitude of static friction is Fs=.
A 10kg block rests on a level floor. A horizontal force of 30N is applied, and μs=0.40. With no other vertical forces, what is the block's actual friction force?
- A
0N, because the block is at rest
- B
Approximately 39.2N, because static friction is always maximal
- C
30N, opposite the applied force
- D
More than 39.2N, because the block has mass
For two bodies in contact, the forces they exert on each other are . Show each force on its body's free-body diagram.
A block rests on a plane inclined at angle θ above the horizontal. There are no other forces with components perpendicular to the plane. Which expression gives the normal force?
- A
N=mgsinθ
- B
N=mgcosθ
- C
N=mgtanθ
- D
N=mg
A block is about to slip downslope on a 30∘ incline. There are no other forces besides gravity and the contact forces, and the block is at impending slip. What is the coefficient of static friction, rounded to three decimal places?
When analyzing a wedge contacting multiple bodies, which procedures are appropriate? Select all that apply.
- A
Draw a separate free-body diagram for the wedge and each body it contacts.
- B
Assume friction points in the same direction at every wedge interface.
- C
Determine the relative tendency to slip at each contact.
- D
Use the limiting static-friction relation only where slip is impending.
Static friction on a driven wheel can point in the same direction as the wheel's motion.
- A
True
- B
False
In what unit must the wrap angle β be expressed when using the limiting capstan relation?
A flexible belt is about to slip on a rough pulley with μs=0.30 and wrap angle β=π radians. What is the limiting ratio Ttight/Tslack, to two decimal places?
- A
Approximately 0.30
- B
Approximately 2.57
- C
Exactly π
- D
Approximately 3.14
Describe a systematic way to determine friction directions and apply the friction model when a wedge contacts multiple bodies. Explain how your approach changes if a contact is sliding rather than at impending slip.
In an equilibrium calculation, you assume a direction for static friction and obtain a negative value for its signed magnitude. What does this result mean?
- A
The body cannot be in equilibrium.
- B
The actual friction direction is opposite the assumed direction.
- C
The coefficient of friction must be negative.
- D
The normal force must be zero.
If an additional applied force has a component perpendicular to an inclined plane, the normal force may differ from mgcosθ, changing the maximum available static friction.
- A
True
- B
False
A friction coefficient describes a pair of surfaces and is not expressed using any measurement unit. What is the unit status of this coefficient?
Which set of conditions must be satisfied by a rigid body in planar static equilibrium?
- A
∑Fx=0, ∑Fy=0, and ∑MO=0
- B
∑Fx=0 and ∑MO=0, but not necessarily ∑Fy=0
- C
∑Fy=0 and ∑MO=0, but not necessarily ∑Fx=0
- D
Zero net force is sufficient; the net moment may be nonzero
A block is sliding across a horizontal surface. If the normal force is 80N and the kinetic-friction coefficient is 0.25, what is the friction force magnitude in the Coulomb model?
- A
0N
- B
20N
- C
32N
- D
80N
A 10kg block rests on a level floor and is pushed horizontally with a 30N force. The coefficient of static friction is 0.40, and there are no other vertical forces. Using g=9.81m/s2, what is the actual static-friction force on the block?
- A
39.2N, equal to the maximum static friction
- B
30N, opposite the applied force
- C
9.8N, equal to the block's weight divided by ten
- D
0N, because the block remains at rest
A 12kg block rests on a plane inclined at 60∘ above the horizontal. No other force has a component perpendicular to the plane. Using g=9.81m/s2, calculate the normal force. Enter your value in newtons to the nearest 0.01N; answers within 0.01N are accepted.