Free Online Flashcard Deck

7 Distributed Loads and Centroids Free Online FlashCards

Study 7 Distributed Loads and Centroids with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What distinguishes a distributed load from a point load?

Back

A distributed load acts over a length, area, or volume rather than at a single point.

02
Front

How do you find a beam load’s equivalent resultant force?

Back

The resultant is the signed area under the intensity curve: R=∫abw(x) dxR=\int_a^b w(x)\,dx.

03
Front

How is the line of action of a distributed load’s resultant located?

Back

Match the original distribution’s moment: xˉ=∫abxw(x) dx∫abw(x) dx\bar{x}=\frac{\int_a^b xw(x)\,dx}{\int_a^b w(x)\,dx}, provided R≠0R\ne 0.

04
Front

What are the resultant and location for a uniform load over length LL?

Back

For intensity w0w_0 over length LL, R=w0LR=w_0L, acting at the rectangle’s centroid, xˉ=L2\bar{x}=\frac{L}{2}.

05
Front

What is the resultant of a triangular load rising to wmax⁡w_{\max} over length LL?

Back

For a triangular load rising from zero to wmax⁡w_{\max} over length LL, the resultant is R=12wmax⁡LR=\frac{1}{2}w_{\max}L.

06
Front

Where does a triangular load’s resultant act along its length?

Back

It acts L3\frac{L}{3} from the end with the larger intensity, or 2L3\frac{2L}{3} from the zero-load end.

07
Front

What is a plane area’s centroid, and how are its coordinates defined?

Back

A centroid is a shape’s geometric balance point. For a plane area, xˉ=1A∫Ax dA\bar{x}=\frac{1}{A}\int_A x\,dA and yˉ=1A∫Ay dA\bar{y}=\frac{1}{A}\int_A y\,dA.

08
Front

Where is the centroid of a rectangle?

Back

A rectangle’s centroid is at the intersection of its diagonals, halfway along each side.

09
Front

Where is a triangle’s centroid relative to its base?

Back

It is at the intersection of the medians, one-third of the altitude from the base, or two-thirds from the opposite vertex.

10
Front

How do you find the centroid of a composite area?

Back

Use area-weighted coordinates: xˉ=∑iAixi∑iAi\bar{x}=\frac{\sum_i A_i x_i}{\sum_i A_i} and yˉ=∑iAiyi∑iAi\bar{y}=\frac{\sum_i A_i y_i}{\sum_i A_i}.

11
Front

How should a hole be represented in a composite-area centroid calculation?

Back

Treat a hole as a negative area when calculating the composite shape’s centroid.

12
Front

How do you combine the resultants of several load shapes?

Back

Add the signed resultants, then use their moments: R=∑iRiR=\sum_i R_i and xˉ=∑iRixi∑iRi\bar{x}=\frac{\sum_i R_i x_i}{\sum_i R_i}, if R≠0R\ne 0.