1 Vectors for Engineering Mechanics

Learn how to represent engineering-mechanics vectors with signed components and use vector operations to analyze forces, projections, and moments.

Vectors and coordinate conventions

A represents a quantity with both magnitude and direction. Force, displacement, and are vectors; mass and time are scalars. In mechanics, vectors may be written in bold or with an arrow, such as F⃗\vec F, and the magnitude of F⃗\vec F may be written as ∣F⃗∣|\vec F| or simply FF.

A ’s components depend on the coordinate axes chosen. State the axes and sign convention before calculating so that the component directions are clear.

Components and unit- notation

In a right-handed Cartesian coordinate system, the unit vectors i\mathbf{i}, j\mathbf{j}, and k\mathbf{k} point along the positive xx-, yy-, and zz-axes. Each has magnitude 11. A in three dimensions is represented as

A⃗=Axi+Ayj+Azk.\vec A=A_x\mathbf{i}+A_y\mathbf{j}+A_z\mathbf{k}.

Here, AxA_x, AyA_y, and AzA_z are , while AxiA_x\mathbf{i}, AyjA_y\mathbf{j}, and AzkA_z\mathbf{k} are the corresponding . A negative component means its component points opposite the positive direction of that axis. In two dimensions, omit the zz-component and the k\mathbf{k} term.

For a of magnitude AA directed at angle θ\theta counterclockwise from the positive xx-axis in a plane, its components are

Ax=Acos⁡θ,Ay=Asin⁡θ.A_x=A\cos\theta,\qquad A_y=A\sin\theta.

For example, a force of 100 N100\,\mathrm{N} directed 30∘30^\circ above the positive xx-axis is

F⃗=(100cos⁡30∘)i+(100sin⁡30∘)j=(86.6i+50.0j) N.\vec F=(100\cos30^\circ)\mathbf{i}+(100\sin30^\circ)\mathbf{j}=(86.6\mathbf{i}+50.0\mathbf{j})\,\mathrm{N}.

The magnitude of a can be recovered from its three-dimensional components:

∣A⃗∣=Ax2+Ay2+Az2.|\vec A|=\sqrt{A_x^2+A_y^2+A_z^2}.

To find the from point P(xP,yP,zP)P(x_P,y_P,z_P) to point Q(xQ,yQ,zQ)Q(x_Q,y_Q,z_Q), subtract the tail coordinates from the head coordinates:

PQ→=(xQ−xP)i+(yQ−yP)j+(zQ−zP)k.\overrightarrow{PQ}=(x_Q-x_P)\mathbf{i}+(y_Q-y_P)\mathbf{j}+(z_Q-z_P)\mathbf{k}.

Specifying a direction with a

A has magnitude 11 and specifies direction alone. For a nonzero A⃗\vec A, the in its direction is

u^A=A⃗∣A⃗∣.\hat{\mathbf{u}}_A=\frac{\vec A}{|\vec A|}.

The original can therefore be expressed as its magnitude multiplied by its direction :

A⃗=∣A⃗∣u^A.\vec A=|\vec A|\hat{\mathbf{u}}_A.

When a force’s magnitude and line of action are known, first determine the direction and then multiply it by the force magnitude.

Addition, subtraction, and multiplication

Add or subtract vectors component by component. For example,

A⃗+B⃗=(Ax+Bx)i+(Ay+By)j+(Az+Bz)k.\vec A+\vec B=(A_x+B_x)\mathbf{i}+(A_y+B_y)\mathbf{j}+(A_z+B_z)\mathbf{k}.

Subtraction is addition of the opposite : A⃗−B⃗=A⃗+(−B⃗)\vec A-\vec B=\vec A+(-\vec B). The resultant of several forces is their sum, found by combining components along the same axis algebraically.

Multiplying a A⃗\vec A by a cc gives a cA⃗c\vec A with magnitude ∣c∣∣A⃗∣|c||\vec A|. A positive value of cc preserves the direction, while a negative value reverses it.

and projections

The of two vectors returns a . It can be calculated from components or from the magnitudes and the angle ϕ\phi between the vectors:

A⃗⋅B⃗=AxBx+AyBy+AzBz=∣A⃗∣∣B⃗∣cos⁡ϕ.\vec A\cdot\vec B=A_xB_x+A_yB_y+A_zB_z=|\vec A||\vec B|\cos\phi.

The can be used to find a component or projection in a specified direction. For nonzero vectors, if A⃗⋅B⃗=0\vec A\cdot\vec B=0, the vectors are perpendicular.

and moments

The returns a perpendicular to both input vectors. Its magnitude depends on the angle ϕ\phi between them:

∣A⃗×B⃗∣=∣A⃗∣∣B⃗∣sin⁡ϕ.|\vec A\times\vec B|=|\vec A||\vec B|\sin\phi.

Its direction follows the right-hand rule. The order of the vectors matters: A⃗×B⃗=−(B⃗×A⃗)\vec A\times\vec B=-(\vec B\times\vec A).

In mechanics, the of a force about a point is given by

M⃗=r⃗×F⃗,\vec M=\vec r\times\vec F,

where r⃗\vec r runs from the point about which the is taken to the force’s point of application.