Free Online Flashcard Deck

01 Functions and Their Graphs Free Online FlashCards

Study 01 Functions and Their Graphs with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What is a function?

Back

A function assigns exactly one output to each allowed input. The allowed inputs form the domain, and the resulting outputs form the range.

02
Front

What does the vertical line test determine?

Back

A graph represents a function of xx if every vertical line intersects it at most once.

03
Front

Evaluate f(3)f(3) for f(x)=x2−4x+1f(x)=x^2-4x+1.

Back

Substitute 33 for every occurrence of xx: f(3)=32−4(3)+1=−2f(3)=3^2-4(3)+1=-2.

04
Front

Find the domain of g(x)=x+2g(x)=\sqrt{x+2}.

Back

The domain is [−2,∞)[-2,\infty), because a real even root requires x+2≥0x+2\ge 0.

05
Front

What are the intercepts of f(x)=x2−4f(x)=x^2-4?

Back

For f(x)=x2−4f(x)=x^2-4, the yy-intercept is (0,−4)(0,-4), and the xx-intercepts are (−2,0)(-2,0) and (2,0)(2,0).

06
Front

What does the horizontal line test determine?

Back

A function is one-to-one if every horizontal line intersects its graph at most once.

07
Front

How does g(x)=(x−3)2g(x)=(x-3)^2 transform y=x2y=x^2?

Back

The graph shifts right 33 units because the input is replaced by x−3x-3.

08
Front

Describe the transformations in g(x)=−2(x−1)2+4g(x)=-2(x-1)^2+4.

Back

Starting from y=x2y=x^2, shift right 11, stretch vertically by 22, reflect across the xx-axis, and shift up 44.

09
Front

In what order is (f∘g)(x)(f\circ g)(x) evaluated?

Back

Apply gg first and then ff: (f∘g)(x)=f(g(x))(f\circ g)(x)=f(g(x)).

10
Front

Find (f∘g)(x)(f\circ g)(x) when f(x)=2x+1f(x)=2x+1 and g(x)=x2g(x)=x^2.

Back

For f(x)=2x+1f(x)=2x+1 and g(x)=x2g(x)=x^2, (f∘g)(x)=2x2+1(f\circ g)(x)=2x^2+1.

11
Front

What conditions define the domain of f∘gf\circ g?

Back

An input must be in the domain of gg, and its output g(x)g(x) must be in the domain of ff.

12
Front

When does a function have an inverse function?

Back

A function must be one-to-one on its domain to have an inverse function.