05 Trigonometric Functions

A progressive guide to measuring angles, using the unit circle, interpreting trigonometric graphs, applying identities, evaluating inverse functions, and solving basic trigonometric equations.

Measuring Angles

An angle is formed by rotating a ray about its endpoint. The starting ray is the initial side, and the ray after rotation is the terminal side. Counterclockwise rotation is positive, while clockwise rotation is negative.

Degrees and radians

Degrees divide a full revolution into 360∘360^\circ. A half revolution is 180∘180^\circ, and a quarter revolution is 90∘90^\circ.

A measures an angle using the ratio of intercepted arc length to radius:

θ=sr.\theta=\frac{s}{r}.

Because a circle has circumference 2πr2\pi r,

360∘=2π radians,180∘=π radians.360^\circ=2\pi\text{ radians},\qquad 180^\circ=\pi\text{ radians}.

Use

radians=degrees⋅π180\text{radians}=\text{degrees}\cdot\frac{\pi}{180}

and

degrees=radians⋅180π.\text{degrees}=\text{radians}\cdot\frac{180}{\pi}.

For example,

60∘=π3,5π4 radians=225∘.60^\circ=\frac{\pi}{3},\qquad \frac{5\pi}{4}\text{ radians}=225^\circ.

Takeaway: Convert all angles to a consistent unit before evaluating or comparing trigonometric expressions.

The and Exact Values

The is centered at the origin and has radius 11:

x2+y2=1.x^2+y^2=1.

Starting at (1,0)(1,0) and rotating counterclockwise through an angle tt, the terminal point is

(x,y)=(cos⁡t,sin⁡t).(x,y)=(\cos t,\sin t).

Thus, the horizontal coordinate gives cosine and the vertical coordinate gives sine. Substitution into the circle equation gives the

sin⁡2t+cos⁡2t=1.\sin^2t+\cos^2t=1.

The signs depend on the quadrant: both sine and cosine are positive in Quadrant I; sine is positive and cosine is negative in Quadrant II; both are negative in Quadrant III; and cosine is positive while sine is negative in Quadrant IV.

Useful first-quadrant coordinates are

  • 0↦(1,0)0\mapsto(1,0)

  • π6↦(32,12)\frac{\pi}{6}\mapsto\left(\frac{\sqrt{3}}{2},\frac{1}{2}\right)

  • π4↦(22,22)\frac{\pi}{4}\mapsto\left(\frac{\sqrt{2}}{2},\frac{\sqrt{2}}{2}\right)

  • π3↦(12,32)\frac{\pi}{3}\mapsto\left(\frac{1}{2},\frac{\sqrt{3}}{2}\right)

  • π2↦(0,1)\frac{\pi}{2}\mapsto(0,1)

The remaining common values follow by symmetry. For an angle outside the first revolution, use periodicity, its quadrant, and its . For example,

sin⁡(7π6)=−sin⁡(π6)=−12.\sin\left(\frac{7\pi}{6}\right)=-\sin\left(\frac{\pi}{6}\right)=-\frac{1}{2}.

The other basic functions are defined by

tan⁡t=sin⁡tcos⁡t,csc⁡t=1sin⁡t,sec⁡t=1cos⁡t,cot⁡t=cos⁡tsin⁡t.\tan t=\frac{\sin t}{\cos t},\qquad \csc t=\frac{1}{\sin t},\qquad \sec t=\frac{1}{\cos t},\qquad \cot t=\frac{\cos t}{\sin t}.

Each expression is defined only when its denominator is nonzero.

Takeaway: The turns angle evaluation into coordinate reading, while the quadrant and determine the sign.

Graphs and Transformations

The basic functions are y=sin⁡xy=\sin x and y=cos⁡xy=\cos x. Each has domain (−∞,∞)( -\infty,\infty ), range [−1,1][-1,1], and period 2π2\pi:

sin⁡(x+2π)=sin⁡x,cos⁡(x+2π)=cos⁡x.\sin(x+2\pi)=\sin x,\qquad \cos(x+2\pi)=\cos x.

Over one period, sine passes through

(0,0),(π2,1),(π,0),(3π2,−1),(2π,0).(0,0),\left(\frac{\pi}{2},1\right),(\pi,0),\left(\frac{3\pi}{2},-1\right),(2\pi,0).

Cosine passes through

(0,1),(π2,0),(π,−1),(3π2,0),(2π,1).(0,1),\left(\frac{\pi}{2},0\right),(\pi,-1),\left(\frac{3\pi}{2},0\right),(2\pi,1).

Tangent is

y=tan⁡x=sin⁡xcos⁡x.y=\tan x=\frac{\sin x}{\cos x}.

It has period π\pi, range (−∞,∞)( -\infty,\infty ), and vertical asymptotes where

x=π2+kπ,k∈Z.x=\frac{\pi}{2}+k\pi,\qquad k\in\mathbb{Z}.

A transformed sinusoid can be written as

y=Asin⁡(B(x−h))+Dy=A\sin(B(x-h))+D

or with cosine in place of sine. Its key features are:

  • : ∣A∣|A|

  • Period: 2π∣B∣\frac{2\pi}{|B|}

  • Horizontal shift: hh

  • Midline: y=Dy=D

  • Maximum: D+∣A∣D+|A|

  • Minimum: D−∣A∣D-|A|

For

y=3sin⁡(2x−π2)+1=3sin⁡(2(x−π4))+1,y=3\sin\left(2x-\frac{\pi}{2}\right)+1=3\sin\left(2\left(x-\frac{\pi}{4}\right)\right)+1,

the is 33, the period is π\pi, the midline is y=1y=1, and the graph shifts right by π4\frac{\pi}{4}.

Takeaway: Read a sinusoidal equation by separating vertical size, horizontal repetition, horizontal position, and vertical position.

Identities and Algebraic Relationships

An identity is an equation that is true for every value in the common domain of its expressions.

The reciprocal and quotient identities are

csc⁡x=1sin⁡x,sec⁡x=1cos⁡x,cot⁡x=1tan⁡x,\csc x=\frac{1}{\sin x},\qquad \sec x=\frac{1}{\cos x},\qquad \cot x=\frac{1}{\tan x},
tan⁡x=sin⁡xcos⁡x,cot⁡x=cos⁡xsin⁡x.\tan x=\frac{\sin x}{\cos x},\qquad \cot x=\frac{\cos x}{\sin x}.

The three principal formulas are

sin⁡2x+cos⁡2x=1,\sin^2x+\cos^2x=1,
1+tan⁡2x=sec⁡2x,1+\tan^2x=\sec^2x,
1+cot⁡2x=csc⁡2x.1+\cot^2x=\csc^2x.

Parity identities show that cosine and secant are even, while sine, cosecant, tangent, and cotangent are odd:

  • cos⁡(−x)=cos⁡x\cos(-x)=\cos x and sec⁡(−x)=sec⁡x\sec(-x)=\sec x

  • sin⁡(−x)=−sin⁡x\sin(-x)=-\sin x, csc⁡(−x)=−csc⁡x\csc(-x)=-\csc x, tan⁡(−x)=−tan⁡x\tan(-x)=-\tan x, and cot⁡(−x)=−cot⁡x\cot(-x)=-\cot x

Sum-and-difference identities include

sin⁡(a±b)=sin⁡acos⁡b±cos⁡asin⁡b,\sin(a\pm b)=\sin a\cos b\pm\cos a\sin b,
cos⁡(a±b)=cos⁡acos⁡b∓sin⁡asin⁡b.\cos(a\pm b)=\cos a\cos b\mp\sin a\sin b.

The double-angle identities include

sin⁡(2x)=2sin⁡xcos⁡x\sin(2x)=2\sin x\cos x

and

cos⁡(2x)=cos⁡2x−sin⁡2x=1−2sin⁡2x=2cos⁡2x−1.\cos(2x)=\cos^2x-\sin^2x=1-2\sin^2x=2\cos^2x-1.

To prove an identity, begin with one side and transform it using known identities until it matches the other side. Monitor excluded values caused by denominators. For example,

sin⁡(π12)=sin⁡(π4−π6)=6−24.\sin\left(\frac{\pi}{12}\right)=\sin\left(\frac{\pi}{4}-\frac{\pi}{6}\right)=\frac{\sqrt{6}-\sqrt{2}}{4}.

Takeaway: Choose identities that simplify the structure, and distinguish an identity that is always true on its domain from an equation whose solutions must be found.

Inverse Trigonometric Functions

The functions sin⁡x\sin x, cos⁡x\cos x, and tan⁡x\tan x repeat, so they are not one-to-one on their full domains. To define an , restrict the original function to an interval on which it is one-to-one.

The standard restrictions are:

  • Sine has restricted domain [−π2,π2]\left[-\frac{\pi}{2},\frac{\pi}{2}\right], so arcsin⁡x\arcsin x has range [−π2,π2]\left[-\frac{\pi}{2},\frac{\pi}{2}\right].

  • Cosine has restricted domain [0,π][0,\pi], so arccos⁡x\arccos x has range [0,π][0,\pi].

  • Tangent has restricted domain (−π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right), so arctan⁡x\arctan x has range (−π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right).

The input restrictions are

arcsin⁡x,arccos⁡x:−1≤x≤1,\arcsin x,\arccos x:\quad -1\le x\le 1,

while arctan⁡x\arctan x accepts every real input. Examples are

arcsin⁡(12)=π6,arccos⁡(−1)=π,arctan⁡(1)=π4.\arcsin\left(\frac{1}{2}\right)=\frac{\pi}{6},\qquad \arccos(-1)=\pi,\qquad \arctan(1)=\frac{\pi}{4}.

The compositions

sin⁡(arcsin⁡x)=x,cos⁡(arccos⁡x)=x,tan⁡(arctan⁡x)=x\sin(\arcsin x)=x,\qquad \cos(\arccos x)=x,\qquad \tan(\arctan x)=x

are valid on the appropriate input domains. The reverse composition must respect the principal range. For example, arcsin⁡(sin⁡x)=x\arcsin(\sin x)=x only when x∈[−π2,π2]x\in\left[-\frac{\pi}{2},\frac{\pi}{2}\right].

If θ=arctan⁡x\theta=\arctan x, a right triangle with opposite side xx, adjacent side 11, and hypotenuse x2+1\sqrt{x^2+1} gives

sin⁡(arctan⁡x)=xx2+1,cos⁡(arctan⁡x)=1x2+1.\sin(\arctan x)=\frac{x}{\sqrt{x^2+1}},\qquad \cos(\arctan x)=\frac{1}{\sqrt{x^2+1}}.

Takeaway: Inverse functions return principal angles, not every angle with the same trigonometric value.

Solving Basic Trigonometric Equations

To solve a basic trigonometric equation, first isolate the trigonometric expression. Then find a or use an inverse function, identify the quadrants where the function has the required sign, and list every solution in the requested interval.

Consider

sin⁡x=12,0≤x<2π.\sin x=\frac{1}{2},\qquad 0\le x<2\pi.

The is π6\frac{\pi}{6}. Sine is positive in Quadrants I and II, so

x=π6,x=5π6.x=\frac{\pi}{6},\qquad x=\frac{5\pi}{6}.

Because sine has period 2π2\pi, all real solutions are

x=π6+2πkorx=5π6+2πk,k∈Z.x=\frac{\pi}{6}+2\pi k\quad\text{or}\quad x=\frac{5\pi}{6}+2\pi k, \qquad k\in\mathbb{Z}.

Use the relevant period for other functions: sine and cosine repeat every 2π2\pi, while tangent repeats every π\pi. Always check domain restrictions before accepting a result, especially when the equation contains a reciprocal or quotient.

Takeaway: A complete solution requires the correct and every quadrant or period that satisfies the original equation.