Free Online Flashcard Deck

10 Sequences and Series Free Online FlashCards

Study 10 Sequences and Series with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What distinguishes a sequence from a series?

Back

A sequence is an ordered list of numbers, while a series is the sum of terms from a sequence.

02
Front

What is a recursive formula?

Back

A recursive formula defines a term using one or more earlier terms and must include an initial value.

03
Front

For an=3n+1a_n=3n+1, what is a20a_{20}?

Back

Using the explicit formula, a20=3(20)+1=61a_{20}=3(20)+1=61.

04
Front

What is the common difference of 12,17,22,27,…12,17,22,27,\ldots?

Back

The common difference is d=17−12=5d=17-12=5, which is also the difference between every pair of consecutive terms.

05
Front

How can two known terms determine an arithmetic sequence's difference?

Back

For two known terms, calculate the common difference with d=aj−aij−id=\frac{a_j-a_i}{j-i}.

06
Front

What is the common ratio of 3,12,48,192,…3,12,48,192,\ldots?

Back

The common ratio is r=12÷3=4r=12\div3=4; each term is multiplied by 4.

07
Front

What is the explicit formula for a geometric sequence?

Back

The explicit formula for a geometric sequence is an=a1rn−1a_n=a_1r^{n-1}.

08
Front

What do the parts of ∑k=1nak\sum_{k=1}^{n}a_k represent?

Back

In ∑k=1nak\sum_{k=1}^{n}a_k, kk is the index, 1 is the starting value, nn is the ending value, and aka_k is the general term.

09
Front

What formula sums the first nn terms of an arithmetic sequence?

Back

The sum of the first nn arithmetic terms is Sn=n2(a1+an)S_n=\frac{n}{2}(a_1+a_n).

10
Front

What formula gives a finite geometric-series sum?

Back

For r≠1r\ne1, the finite geometric sum is Sn=a11−rn1−rS_n=a_1\frac{1-r^n}{1-r}.

11
Front

When does an infinite geometric series converge to a finite sum?

Back

An infinite geometric series has a finite sum only when ∣r∣<1|r|<1.

12
Front

Find the sum of 12+6+3+32+⋯12+6+3+\frac{3}{2}+\cdots.

Back

Here a1=12a_1=12 and r=12r=\frac{1}{2}, so S∞=121−12=24S_\infty=\frac{12}{1-\frac{1}{2}}=24.