06 Substitution and Elimination Reactions
Compare the SN1, SN2, E1, and E2 pathways and use substrate structure, reagent strength, solvent, and geometry to predict products.
A framework for the four pathways
Substitution replaces a leaving group attached to carbon with a nucleophile. Elimination removes a leaving group and a neighboring hydrogen to form a carbon–carbon double bond. The four principal pathways are , , , and .
A useful first distinction is whether the reaction is concerted or proceeds through an intermediate:
and are concerted: the relevant bonds form and break in a single step.
and proceed through a intermediate.
The numbers in the pathway names correspond to the number of reactants involved in the rate-determining step. For the idealized mechanisms, the rate laws are:
and :
and :
These patterns are useful guides, but reaction conditions and substrate structure work together; no single factor always determines the outcome.
Nucleophilic substitution
In , the nucleophile attacks the carbon from the side opposite the leaving group. As the new bond forms, the bond to the leaving group breaks. This backside attack inverts the geometry at a stereogenic reaction center. The geometry inverts, although the formal or label does not necessarily change because substituent priorities may differ between reactant and product.
is most accessible at methyl and primary carbons, can be slower at secondary carbons, and is generally blocked by crowding at tertiary carbons. A strong, unhindered nucleophile and a good leaving group favor this pathway. Polar aprotic solvents such as acetone, DMSO, and acetonitrile commonly keep anionic nucleophiles relatively reactive.
For example, cyanide can replace bromide on a primary carbon:
In , the leaving group departs first, forming a planar, approximately -hybridized . A nucleophile then attacks; if the nucleophile is neutral, a proton-transfer step may follow. Because formation is usually the slow step, the rate depends on substrate concentration rather than nucleophile concentration.
is favored when the substrate can form a stable , as is common for tertiary, benzylic, and allylic substrates. Polar protic solvents help stabilize ions, and weak or neutral nucleophiles can participate. Attack on either face of a chiral often gives partial to substantial racemization, but not necessarily a perfectly even mixture. Hydride or alkyl shifts may occur if they create a more stable .
For instance, tert-butyl bromide can react with water to form tert-butanol: bromide leaves, water attacks the , and deprotonation produces the alcohol. Takeaway: substrate accessibility and nucleophile strength help distinguish the concerted route from the -based route.
Elimination and alkene formation
In , a base removes a β-hydrogen—a hydrogen attached to a carbon neighboring the carbon bearing the leaving group. The electrons from the carbon–hydrogen bond form the double bond as the leaving group departs. A strong base favors , especially with secondary and tertiary substrates; a bulky base can favor elimination over substitution.
The carbon–hydrogen bond and carbon–leaving-group bond generally need to be . This geometrical requirement makes stereospecific: the arrangement of the substrate constrains the alkene product. In cyclohexane rings, the relevant hydrogen and leaving group usually must both be axial and trans to one another.
When more than one alkene can form, a small base often favors the more substituted . A bulky base may instead favor the less substituted Hofmann alkene because it can more readily remove a less hindered β-hydrogen. These are trends, not guarantees; available hydrogens and geometric constraints matter. For example, 2-bromobutane with ethoxide gives mainly 2-butene, with some 1-butene, while a bulky base can increase the proportion of 1-butene.
In , the leaving group departs first to form a . A base then removes a β-hydrogen, and the electrons from the carbon–hydrogen bond form the double bond. shares its first step with , so the pathways often compete under conditions that support carbocations. Heating often increases elimination relative to substitution. Rearrangements can occur before the alkene forms, and the more substituted, more stable alkene is generally favored when possible. Takeaway: depends on base strength and suitable geometry, whereas proceeds through a and often competes with .
Predicting the pathway and product
Use the following evidence together to predict the likely pathway and product:
Check the substrate. Methyl and primary substrates commonly favor with a good nucleophile. Tertiary substrates are too crowded for ordinary ; they commonly undergo with a strong base or / when a stable can form. Secondary substrates depend strongly on the conditions.
Classify the reagent. A strong nucleophile that is not a strong base favors on an accessible substrate. A strong base favors , particularly with secondary or tertiary substrates. Weak, neutral nucleophiles such as water or alcohols can support / when formation is favorable.
Consider solvent and temperature. Polar aprotic solvents commonly support . Polar protic solvents stabilize ions and commonly support /. Heating often increases the relative importance of elimination.
Draw the mechanism and check the product. For substitution, replace the leaving group and account for inversion or stereochemistry. For elimination, remove a β-hydrogen, form the double bond, and check regiochemistry and geometry. Include competing products when more than one pathway is plausible.
Leaving-group ability matters in all four pathways. Iodide, bromide, and sulfonate groups such as tosylate are common good leaving groups. Hydroxide is generally a poor leaving group unless it is converted into water or another better leaving group.
As a compact comparison: choose between concerted and pathways first, then use substrate, reagent, solvent, temperature, leaving-group ability, and stereochemical constraints to refine the prediction. These guidelines describe common introductory cases; unusual substrates and competing pathways can change the outcome.