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1 Integration Techniques Free Online FlashCards

Study 1 Integration Techniques with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What is an antiderivative?

Back

An antiderivative of ff is a function FF satisfying F′(x)=f(x)F'(x)=f(x) on the interval.

02
Front

Why does an indefinite integral include +C+C?

Back

The indefinite integral represents all antiderivatives: ∫f(x) dx=F(x)+C\int f(x)\,dx=F(x)+C, where CC is an arbitrary constant.

03
Front

State the power rule for integration.

Back

For n≠−1n\ne -1, ∫xn dx=xn+1n+1+C\int x^n\,dx=\frac{x^{n+1}}{n+1}+C. The case n=−1n=-1 instead gives ∫1x dx=ln⁡∣x∣+C\int \frac{1}{x}\,dx=\ln|x|+C.

04
Front

What does a definite integral represent?

Back

A definite integral is signed accumulation: regions below the xx-axis contribute negatively. If f(x)≥0f(x)\ge 0 on [a,b][a,b], it equals the geometric area under the graph.

05
Front

State Part 1 of the Fundamental Theorem of Calculus.

Back

If F(x)=∫axf(t) dtF(x)=\int_a^x f(t)\,dt and ff is continuous, then F′(x)=f(x)F'(x)=f(x).

06
Front

State Part 2 of the Fundamental Theorem of Calculus.

Back

If F′=fF' = f on [a,b][a,b], then ∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx=F(b)-F(a). This evaluates a definite integral from any antiderivative.

07
Front

What is the purpose of uu-substitution?

Back

Choose u=g(x)u=g(x), compute du=g′(x) dxdu=g'(x)\,dx, rewrite the integral in uu, integrate, and substitute back. This reverses the chain rule.

08
Front

State the integration-by-parts formula.

Back

Integration by parts uses ∫u dv=uv−∫v du\int u\,dv=uv-\int v\,du. It is based on reversing the product rule and is useful for suitable products.

09
Front

How are odd powers handled in sine–cosine integrals?

Back

For ∫sin⁡mxcos⁡nx dx\int \sin^m x\cos^n x\,dx, save one sine factor when mm is odd or one cosine factor when nn is odd, then use a Pythagorean identity.

10
Front

Match each radical form to its trigonometric substitution.

Back

Use x=asin⁡θx=a\sin\theta for a2−x2\sqrt{a^2-x^2}, x=atan⁡θx=a\tan\theta for a2+x2\sqrt{a^2+x^2}, and x=asec⁡θx=a\sec\theta for x2−a2\sqrt{x^2-a^2}.

11
Front

When is partial-fraction decomposition applicable?

Back

Partial fractions applies to rational functions after polynomial division if needed. Distinct linear factors receive constant numerators; an irreducible quadratic receives a linear numerator.

12
Front

What is the midpoint rule formula?

Back

With Δx=b−an\Delta x=\frac{b-a}{n}, the midpoint rule is Mn=Δx∑i=1nf(xi−1+xi2)M_n=\Delta x\sum_{i=1}^n f\left(\frac{x_{i-1}+x_i}{2}\right).