Which condition guarantees that the geometric series converges?
6 Infinite Series and Convergence Tests Online Quiz Questions
Use this free practice quiz with 20 questions to review 6 Infinite Series and Convergence Tests, test your knowledge, and prepare for your next test or exam.
Evaluate the telescoping series ∑n=1∞n(n+1)1.
- A
1
- B
0
- C
21
- D
The series diverges
What is the correct conclusion for ∑n=1∞n3/21?
- A
It diverges because p<2.
- B
It diverges because every p-series diverges.
- C
It converges because p>1.
- D
The p-series test is inconclusive for this value.
Which statements correctly describe comparison tests for series? Select all correct choices.
- A
The direct comparison test is primarily used for nonnegative terms.
- B
The limit comparison test applies when the limiting ratio is zero.
- C
The limit comparison test applies when the limiting ratio lies strictly between 0 and infinity.
- D
The direct comparison test requires the two series to have equal sums.
Which conditions are required by the alternating series test? Select all correct choices.
- A
The signs must eventually be positive.
- B
The term magnitudes must eventually decrease.
- C
The series of absolute values must converge.
- D
The term magnitudes must approach zero.
True or false: If limn→∞an=0, then the series ∑n=1∞an must converge.
- A
True
- B
False
True or false: If the ratio-test limit L=limn→∞∣an+1/an∣ is less than 1, then the series converges absolutely.
- A
True
- B
False
What is the sum of ∑n=1∞3(41)n−1? Enter the numerical answer as a simplified decimal or fraction.
What is the convergence classification of ∑n=1∞n(−1)n−1? Enter one concise classification.
The harmonic series \sum_{n=}^{\infty}\frac{1}{n} has p=1, so it .
Using the root test, ∑n=1∞(5n2n+1)n because its root-test limit is 52.
Use the limit comparison test to determine whether ∑n=1∞n3−23n2+1 converges or diverges. Show the comparison limit and justify your conclusion.
For a series, the ratio-test limit is L=1. What conclusion does the ratio test itself provide?
- A
The series converges absolutely.
- B
The ratio test is inconclusive.
- C
The series diverges.
- D
The series is conditionally convergent.
If ∑n=1∞(bn−bn+1) has b1=5 and limn→∞bn+1=2, what is its sum?
- A
b1+L
- B
L−b1
- C
b1−L
- D
The series always diverges
Determine whether the geometric series ∑n=0∞4(−23)n converges or diverges.
- A
The series converges because r is positive.
- B
The series diverges because ∣r∣>1.
- C
The series converges to −2.
- D
The series diverges because its first term is negative.
What conclusion follows for the series ∑n=1∞n3/21?
- A
It diverges because the exponent is less than 2.
- B
It diverges because every reciprocal-power series diverges.
- C
It converges because 23>1.
- D
It converges only if its first term is less than 1.
Classify the series ∑n=1∞n(−1)n−1.
- A
It converges by the alternating series test.
- B
It diverges because the harmonic series is divergent.
- C
It converges absolutely by the p-series test.
- D
It diverges because its terms alternate in sign.
True or false: If the ratio-test limit limn→∞anan+1 equals 1, the series must diverge.
- A
True
- B
False
Enter the sum of the geometric series ∑n=1∞3(41)n−1 as a simplified number.
For the series ∑n=1∞n3−23n2+1, enter whether the series converges or diverges.