5 Sequences

A structured guide to defining sequences, evaluating their limits, and proving convergence or divergence using limit laws, bounds, monotonicity, the Squeeze Theorem, and recursive methods.

Sequences and Their Definitions

A is an ordered list of real numbers indexed by the positive integers:

{an}n=1∞=a1,a2,a3,…\{a_n\}_{n=1}^{\infty}=a_1,a_2,a_3,\ldots

The index nn is an integer, and ana_n denotes the nnth term. A can be given explicitly, such as

an=2n+1n+3,a_n=\frac{2n+1}{n+3},

or recursively, by specifying initial values and a rule for producing later terms. For example,

a1=1,an+1=an+32.a_1=1,\qquad a_{n+1}=\frac{a_n+3}{2}.

An explicit formula calculates a term directly from its index. A recursive rule calculates each new term from previously known terms, so the initial information is essential.

Takeaway: A is a discrete function whose inputs are positive integers, and its terms may be defined directly or through a recurrence.

Limits of Sequences

A to a real number LL when its terms become arbitrarily close to LL for sufficiently large indices. The notation is

lim⁡n→∞an=Loran→L.\lim_{n\to\infty}a_n=L \qquad\text{or}\qquad a_n\to L.

Formally, convergence means that for every ε>0\varepsilon>0, there is an integer NN such that

∣an−L∣<εwhenever n≥N.\lvert a_n-L\rvert<\varepsilon \qquad\text{whenever }n\ge N.

The integer NN may depend on ε\varepsilon. Once n≥Nn\ge N, every term lies in the interval (L−ε,L+ε)(L-\varepsilon,L+\varepsilon).

If no finite real number satisfies this condition, the . For example,

1n→0,\frac{1}{n}\to0,

whereas (−1)n(-1)^n because its terms alternate between 11 and −1-1. The n2n^2 also because its terms grow without bound. The notation an→∞a_n\to\infty describes unbounded growth rather than convergence to a finite real number.

Takeaway: Convergence concerns the eventual behavior of all terms, not whether the is merely or whether some terms are close to a particular value.

Computing Limits

When a has the form an=f(n)a_n=f(n), a known function limit can often be used. If

lim⁡x→∞f(x)=L,\lim_{x\to\infty}f(x)=L,

then

lim⁡n→∞an=L.\lim_{n\to\infty}a_n=L.

For example,

lim⁡n→∞3n2−1n2+4=lim⁡n→∞3−1/n21+4/n2=3.\lim_{n\to\infty}\frac{3n^2-1}{n^2+4} =\lim_{n\to\infty}\frac{3-1/n^2}{1+4/n^2}=3.

Frequently useful limits include

lim⁡n→∞1np=0(p>0),lim⁡n→∞rn=0(∣r∣<1),lim⁡n→∞(1−1n)=1.\lim_{n\to\infty}\frac{1}{n^p}=0\quad(p>0), \qquad \lim_{n\to\infty}r^n=0\quad(\lvert r\rvert<1), \qquad \lim_{n\to\infty}\left(1-\frac{1}{n}\right)=1.

If an→La_n\to L and bn→Mb_n\to M, then the limit laws give

lim⁡n→∞(an+bn)=L+M,\lim_{n\to\infty}(a_n+b_n)=L+M,
lim⁡n→∞(an−bn)=L−M,\lim_{n\to\infty}(a_n-b_n)=L-M,
lim⁡n→∞anbn=LM,\lim_{n\to\infty}a_nb_n=LM,

and, when M≠0M\ne0,

lim⁡n→∞anbn=LM.\lim_{n\to\infty}\frac{a_n}{b_n}=\frac{L}{M}.

Continuity also transfers limits: if gg is continuous at LL, then

lim⁡n→∞g(an)=g(L).\lim_{n\to\infty}g(a_n)=g(L).

For example, if an→4a_n\to4, then

lim⁡n→∞an+5=9=3.\lim_{n\to\infty}\sqrt{a_n+5}=\sqrt{9}=3.

Takeaway: Simplify expressions using familiar function limits, algebraic limit laws, and continuity.

The

The is useful when a is difficult to evaluate directly. Suppose that, for all sufficiently large nn,

bn≤an≤cn,b_n\le a_n\le c_n,

and both outside sequences have the same limit:

lim⁡n→∞bn=lim⁡n→∞cn=L.\lim_{n\to\infty}b_n= \lim_{n\to\infty}c_n=L.

Then

lim⁡n→∞an=L.\lim_{n\to\infty}a_n=L.

For example, the sine function always satisfies −1≤sin⁡n≤1-1\le\sin n\le1. Dividing by the positive number nn gives

−1n≤sin⁡nn≤1n.-\frac{1}{n}\le\frac{\sin n}{n}\le\frac{1}{n}.

Both outside sequences approach zero, so the yields

lim⁡n→∞sin⁡nn=0.\lim_{n\to\infty}\frac{\sin n}{n}=0.

The inequalities need only hold from some index onward; finitely many initial terms do not affect a finite limit.

Takeaway: To use the theorem, trap the target between two simpler sequences that approach the same value.

Monotonicity and Boundedness

Monotonicity describes the direction of change between consecutive terms. A is nondecreasing when

an+1≥an,a_{n+1}\ge a_n,

and nonincreasing when

an+1≤an.a_{n+1}\le a_n.

A is if it is nondecreasing or nonincreasing. To test this property, examine the sign of

an+1−an,a_{n+1}-a_n,

or, for positive terms, compare the ratio an+1/ana_{n+1}/a_n.

For

an=1−1n,a_n=1-\frac{1}{n},

we have

an+1−an=(1−1n+1)−(1−1n)=1n(n+1)>0,a_{n+1}-a_n =\left(1-\frac{1}{n+1}\right)-\left(1-\frac{1}{n}\right) =\frac{1}{n(n+1)}>0,

so the is increasing.

Monotonicity alone does not guarantee convergence. The an=na_n=n is increasing but has no finite limit because it is unbounded. A bound in the appropriate direction is also needed.

A is above if some number UU satisfies an≤Ua_n\le U for every nn. It is below if some number LL satisfies an≥La_n\ge L for every nn. It is when both conditions hold. Every convergent is , but a need not converge; (−1)n(-1)^n is a counterexample.

Takeaway: Monotonicity controls direction, while boundedness prevents continued escape. Together, in the correct directions, they establish convergence.

Proving Convergence for Recursive Sequences

The provides a practical convergence test:

  • Every increasing that is above .

  • Every decreasing that is below .

This theorem is especially useful for recursive sequences, whose general terms may be difficult to express explicitly.

Consider

a1=1,an+1=2+an.a_1=1, \qquad a_{n+1}=\sqrt{2+a_n}.

First, prove the upper bound an≤2a_n\le2. The claim is true for a1=1a_1=1. If an≤2a_n\le2, then

an+1=2+an≤4=2.a_{n+1}=\sqrt{2+a_n}\le\sqrt{4}=2.

Therefore, induction proves that every term is at most 22.

Next, prove that the is increasing. Since a1≤a2a_1\le a_2, suppose an≥an−1a_n\ge a_{n-1}. Because the square-root function is increasing,

an+1=2+an≥2+an−1=an.a_{n+1}=\sqrt{2+a_n} \ge\sqrt{2+a_{n-1}}=a_n.

Thus the is increasing and above, so it . Write its limit as LL. Taking limits in the recurrence gives the

L=2+L.L=\sqrt{2+L}.

Since every term is nonnegative, L≥0L\ge0. Squaring produces

L2=2+L,L2−L−2=0,(L−2)(L+1)=0.L^2=2+L, \qquad L^2-L-2=0, \qquad (L-2)(L+1)=0.

The algebraic candidates are L=2L=2 and L=−1L=-1. The bound L≥0L\ge0 rejects L=−1L=-1, so

lim⁡n→∞an=2.\lim_{n\to\infty}a_n=2.

The supplies only possible limits. A separate convergence argument is required before taking limits in the recurrence, and bounds or other properties must be used to discard incompatible algebraic solutions.

Takeaway: For a , a reliable order of work is to compute initial terms, prove a bound, prove monotonicity, apply the , and then solve the resulting .

Convergence and Divergence Strategies

Several criteria organize decisions about convergence and divergence:

  1. If an→La_n\to L, then the is .

  2. A with a bound in the appropriate direction .

  3. If subsequences approach different values, the full cannot converge. For example, the even and odd subsequences of (−1)n(-1)^n approach different values.

  4. A whose terms become arbitrarily large in magnitude cannot converge to a finite real number.

  5. Changing finitely many initial terms does not change convergence or the value of a finite limit.

These criteria should be applied strategically. Direct algebra is often best for a rational expression, the is useful for oscillatory expressions with shrinking magnitude, and monotonicity plus boundedness is particularly effective for recursively defined terms.

Final summary: A is an ordered list indexed by positive integers. To analyze it, identify its definition, determine whether its terms approach a single value, and choose an appropriate proof method. Limit laws evaluate many explicit formulas; the handles useful inequalities; and the combination of monotonicity and boundedness proves convergence even when no explicit formula is available.