What is a power series centered at ?
A power series centered at has the form , where the are constants.
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What is a power series centered at a?
A power series centered at a has the form ∑n=0∞cn(x−a)n, where the cn are constants.
When does the geometric series converge?
The geometric series satisfies ∑n=0∞rn=1−r1 when ∣r∣<1.
What is the radius of convergence?
The radius of convergence is the number R such that a series centered at a converges for ∣x−a∣<R and diverges for ∣x−a∣>R.
What is the interval of convergence?
The interval of convergence is the complete set of real x-values for which the power series converges, including any endpoints that pass their tests.
How should endpoints be handled after finding R?
For a power series, the ratio test usually gives ∣x−a∣<R. The boundary values x=a−R and x=a+R must then be tested separately.
What are the radius and interval for ∑n=1∞n3n(x−2)n?
For ∑n=1∞n3n(x−2)n, the radius is R=3 and the interval of convergence is [−1,5).
How is a power series differentiated within its radius?
Inside ∣x−a∣<R, differentiation is term-by-term: dxd∑n=0∞cn(x−a)n=∑n=1∞ncn(x−a)n−1.
How is a power series integrated term by term?
Inside the interval of convergence, integrate term-by-term: ∫∑n=0∞cn(x−a)ndx=C+∑n=0∞n+1cn(x−a)n+1.
What is the Taylor series of f about a?
The Taylor series of f about a is ∑n=0∞n!f(n)(a)(x−a)n.
What is a Maclaurin series?
A Maclaurin series is a Taylor series centered at a=0: ∑n=0∞n!f(n)(0)xn.
What is the Maclaurin series for ex?
The Maclaurin series for ex is ∑n=0∞n!xn, and its radius of convergence is R=∞.
What is the convergence interval for the series of ln(1+x)?
The series ln(1+x)=∑n=1∞(−1)n+1nxn converges on −1<x≤1.