Free Online Flashcard Deck

03/14 3. Inequalities Free Online FlashCards

Study 03/14 3. Inequalities with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

When must an inequality symbol be reversed?

Back

Reverse the inequality symbol when multiplying or dividing both sides by a negative number.

02
Front

Solve 4x−7≤94x-7\le 9.

Back

The solution is x≤4x\le 4, which is (−∞,4](-\infty,4] in interval notation.

03
Front

What happens when simplifying removes the variable?

Back

A true statement after simplification gives all real numbers; a false statement gives no solutions, written ∅\varnothing.

04
Front

What does “and” mean in a compound inequality?

Back

An “and” compound inequality represents the intersection of its solution sets: values satisfying both conditions.

05
Front

What does “or” mean in a compound inequality?

Back

An “or” compound inequality represents the union of its solution sets: values satisfying at least one condition.

06
Front

Solve ∣2x−3∣=7|2x-3|=7.

Back

Set the expression equal to both 77 and −7-7: 2x−3=72x-3=7 or 2x−3=−72x-3=-7. Thus, x=5x=5 or x=−2x=-2.

07
Front

Solve ∣x−4∣≤3|x-4|\le 3.

Back

Rewrite it as −3≤x−4≤3-3\le x-4\le 3, then solve: 1≤x≤71\le x\le 7, or [1,7][1,7].

08
Front

Solve ∣2x+1∣>5|2x+1|>5.

Back

Rewrite it as 2x+1<−52x+1<-5 or 2x+1>52x+1>5. The solution is x<−3x<-3 or x>2x>2.

09
Front

What do brackets and parentheses mean in interval notation?

Back

A bracket means the endpoint is included; a parenthesis means the endpoint is excluded.

10
Front

Why does infinity always have a parenthesis?

Back

Infinity always uses a parenthesis because infinity is not a real number and cannot be included.

11
Front

How do inequality symbols determine number-line graphs?

Back

Use an open circle for << or >>, and a closed circle for ≤\le or ≥\ge. Shade the region containing the solutions.

12
Front

How many notebooks can cost at most $80\$80 after a $20\$20 fee?

Back

Model the cost with 20+6n≤8020+6n\le 80. Since nn counts notebooks, the meaningful solutions are n∈{0,1,2,…,10}n\in\{0,1,2,\ldots,10\}.