Free Online Flashcard Deck

07/14 7. Quadratic Functions and Equations Free Online FlashCards

Study 07/14 7. Quadratic Functions and Equations with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What is the standard form of a quadratic function?

Back

A quadratic function has the form f(x)=ax2+bx+cf(x)=ax^2+bx+c, where a≠0a\ne0. Its graph is a parabola.

02
Front

How does the sign of aa affect a parabola?

Back

If a>0a>0, the parabola opens upward and has a minimum; if a<0a<0, it opens downward and has a maximum.

03
Front

What does vertex form reveal immediately?

Back

For f(x)=a(x−h)2+kf(x)=a(x-h)^2+k, the vertex is (h,k)(h,k) and the axis of symmetry is x=hx=h.

04
Front

What do the factors reveal in factored form?

Back

For f(x)=a(x−r1)(x−r2)f(x)=a(x-r_1)(x-r_2), the zeros are x=r1x=r_1 and x=r2x=r_2, giving the xx-intercepts.

05
Front

How do you find the vertex from standard form?

Back

For f(x)=ax2+bx+cf(x)=ax^2+bx+c, the axis of symmetry is x=−b2ax=-\frac{b}{2a}. Evaluate the function there to find the vertex's yy-coordinate.

06
Front

Find the vertex of f(x)=x2−6x+5f(x)=x^2-6x+5.

Back

The vertex is (3,−4)(3,-4), because the axis is x=3x=3 and f(3)=−4f(3)=-4.

07
Front

What is the zero-product property?

Back

If uv=0uv=0, then u=0u=0 or v=0v=0. This lets you solve a factored quadratic by setting each factor equal to zero.

08
Front

Solve x2−7x+12=0x^2-7x+12=0 by factoring.

Back

Factor: x2−7x+12=(x−3)(x−4)x^2-7x+12=(x-3)(x-4). Therefore, x=3x=3 or x=4x=4.

09
Front

What quantity completes the square in x2+bxx^2+bx?

Back

For x2+bxx^2+bx, add (b2)2\left(\frac{b}{2}\right)^2 to complete the square. Add the same quantity to both sides of an equation.

10
Front

Solve x2+6x−7=0x^2+6x-7=0 by completing the square.

Back

Rewrite as (x+3)2=16(x+3)^2=16, then use both square roots: x+3=±4x+3=\pm4. Thus, x=1x=1 or x=−7x=-7.

11
Front

What is the quadratic formula?

Back

For ax2+bx+c=0ax^2+bx+c=0, use x=−b±b2−4ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. It solves every quadratic equation in standard form.

12
Front

How does the discriminant classify solutions?

Back

The discriminant is Δ=b2−4ac\Delta=b^2-4ac. If Δ>0\Delta>0, there are two distinct real solutions; if Δ=0\Delta=0, one repeated real solution; if Δ<0\Delta<0, no real solutions.