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11/14 11. Logarithmic Functions and Equations Free Online FlashCards

Study 11/14 11. Logarithmic Functions and Equations with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

Evaluate log⁡5(125)\log_5(125).

Back

log⁡5(125)=3\log_5(125)=3, because 53=1255^3=125.

02
Front

What are common and natural logarithms?

Back

A common logarithm has base 1010: log⁡(x)=log⁡10(x)\log(x)=\log_{10}(x). A natural logarithm has base ee: ln⁡(x)=log⁡e(x)\ln(x)=\log_e(x).

03
Front

State the product property of logarithms.

Back

The product property is log⁡b(MN)=log⁡b(M)+log⁡b(N)\log_b(MN)=\log_b(M)+\log_b(N), for positive MM and NN.

04
Front

State the quotient property of logarithms.

Back

The quotient property is log⁡b(MN)=log⁡b(M)−log⁡b(N)\log_b\left(\frac{M}{N}\right)=\log_b(M)-\log_b(N), for positive MM and NN.

05
Front

How does the power property rewrite log⁡b(Mp)\log_b(M^p)?

Back

The power property is log⁡b(Mp)=plog⁡b(M)\log_b(M^p)=p\log_b(M). The exponent becomes a coefficient.

06
Front

What is the change-of-base formula?

Back

log⁡b(x)=ln⁡(x)ln⁡(b)\log_b(x)=\frac{\ln(x)}{\ln(b)}, so log⁡5(17)=ln⁡(17)ln⁡(5)\log_5(17)=\frac{\ln(17)}{\ln(5)}.

07
Front

Can log⁡b(x+y)\log_b(x+y) be split into two logarithms?

Back

No. Logarithm properties do not separate sums: log⁡b(x+y)≠log⁡b(x)+log⁡b(y)\log_b(x+y)\neq\log_b(x)+\log_b(y).

08
Front

What are the domain, range, and asymptote of y=log⁡b(x)y=\log_b(x)?

Back

For y=log⁡b(x)y=\log_b(x), the domain is (0,∞)(0,\infty), the range is all real numbers, and the vertical asymptote is x=0x=0.

09
Front

When is a parent logarithmic graph increasing?

Back

The graph of y=log⁡b(x)y=\log_b(x) is increasing when b>1b>1 and decreasing when 0<b<10<b<1.

10
Front

How do hh and kk affect alog⁡b(x−h)+ka\log_b(x-h)+k?

Back

For f(x)=alog⁡b(x−h)+kf(x)=a\log_b(x-h)+k, the domain is x>hx>h, the vertical asymptote is x=hx=h, and the range remains all real numbers.

11
Front

Solve log⁡3(2x−1)=4\log_3(2x-1)=4.

Back

Convert to exponential form: 2x−1=34=812x-1=3^4=81. Thus x=41x=41, and the logarithm argument is positive.

12
Front

Solve log⁡5(x+1)=log⁡5(3x−7)\log_5(x+1)=\log_5(3x-7).

Back

Because the bases match, set the arguments equal: x+1=3x−7x+1=3x-7. Therefore, x=4x=4, and both arguments equal 55.