Free Online Flashcard Deck

3 - Two-Dimensional Kinematics Free Online FlashCards

Study 3 - Two-Dimensional Kinematics with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

How is a two-dimensional motion problem usually separated?

Back

Choose axes first, then analyze the perpendicular components independently using one-dimensional kinematic equations that share the same time variable.

02
Front

What is displacement?

Back

Displacement is the vector from the initial position to the final position: Δr⃗=r⃗f−r⃗i\Delta\vec r=\vec r_f-\vec r_i.

03
Front

What do slopes represent on motion graphs?

Back

The slope of a position-versus-time graph gives velocity, while the slope of a velocity-versus-time graph gives acceleration.

04
Front

How are a vector’s components found?

Back

For a vector of magnitude AA at angle θ\theta, Ax=Acos⁡θA_x=A\cos\theta and Ay=Asin⁡θA_y=A\sin\theta.

05
Front

How are two vectors added?

Back

Add corresponding components: A⃗+B⃗=(Ax+Bx)i^+(Ay+By)j^\vec A+\vec B=(A_x+B_x)\hat i+(A_y+B_y)\hat j. Do not add magnitudes unless the vectors are parallel.

06
Front

What is the definition of average velocity?

Back

Average velocity equals displacement divided by elapsed time: v⃗avg=Δr⃗Δt\vec v_{\text{avg}}=\frac{\Delta\vec r}{\Delta t}.

07
Front

How is constant-acceleration motion analyzed in two dimensions?

Back

For constant acceleration, analyze the perpendicular components separately with one-dimensional kinematic equations; both components use the same time tt.

08
Front

What are the acceleration components of an ideal projectile?

Back

For ideal projectile motion, ax=0a_x=0 and ay=−ga_y=-g, so acceleration is vertically downward.

09
Front

What is true at a projectile’s highest point?

Back

At the highest point, vy=0v_y=0, but vxv_x generally remains nonzero and acceleration is still a⃗=−gj^\vec a=-g\hat j.

10
Front

When does the standard projectile flight-time formula apply?

Back

For equal launch and landing heights, tflight=2v0sin⁡θgt_{\text{flight}}=\frac{2v_0\sin\theta}{g}, assuming negligible air resistance.

11
Front

How is the range of a horizontal launch determined?

Back

For a horizontal launch, v0y=0v_{0y}=0. Find the flight time from vertical motion, then use Δx=v0xt\Delta x=v_{0x}t.

12
Front

How is relative velocity calculated?

Back

Relative velocity is found by vector subtraction: v⃗A/B=v⃗A−v⃗B\vec v_{A/B}=\vec v_A-\vec v_B.