02/14 Atomic Structure and the Periodic Table

A structured guide to atomic theory, subatomic particles, isotopes, electron configurations, periodic trends, and the connection between atomic structure and chemical behavior.

Atomic Theory and the Structure of Matter

Modern atomic theory developed as experiments revealed that atoms are not indivisible spheres. An atom consists of a small, dense nucleus surrounded by an electron cloud. The nucleus contains positively charged protons and neutral neutrons, while negatively charged electrons occupy regions of space around the nucleus.

Nearly all the atom’s mass is concentrated in the nucleus, but nearly all its volume is associated with the electron cloud. An atom has a diameter of about 10−10 m10^{-10}\,\mathrm{m}, while its nucleus is approximately 10−15 m10^{-15}\,\mathrm{m} in diameter.

The identity of an element is determined by its number of protons. Chemical reactions usually rearrange electrons while leaving the nuclei unchanged, so ordinary chemical reactions do not change one element into another. Atoms combine in definite ratios because their electrons interact in predictable ways.

Quantum mechanics provides the current model of electron behavior. Electrons do not move in fixed circular paths. Instead, an orbital is a mathematical region in which an electron is likely to be found. Each orbital can contain no more than two electrons with opposite spins.

Takeaway: The nucleus determines most of an atom’s mass and identity, while the electron arrangement largely determines chemical behavior.

Subatomic Particles, Isotopes, and Ions

The three major subatomic particles differ in charge, mass, and location:

  • A proton, p+p^+, has relative charge +1+1, approximate relative mass 11, and is located in the nucleus.

  • A neutron, n0n^0, has charge 00, approximate relative mass 11, and is located in the nucleus.

  • An electron, e−e^-, has charge −1-1, approximate relative mass 1/18361/1836, and occupies the electron cloud.

The is the number of protons:

Z=number of protonsZ=\text{number of protons}

The is the number of protons plus neutrons:

A=number of protons+number of neutronsA=\text{number of protons}+\text{number of neutrons}

Therefore, the number of neutrons is A−ZA-Z. For example, 1123Na{}^{23}_{11}\mathrm{Na} contains 1111 protons and 23−11=1223-11=12 neutrons. If the atom is neutral, it also contains 1111 electrons.

For an , use the charge to determine the electron count:

q=number of protons−number of electronsq=\text{number of protons}-\text{number of electrons}

Thus, Mg2+\mathrm{Mg^{2+}} has 1212 protons and 1010 electrons, while Cl−\mathrm{Cl^-} has 1717 protons and 1818 electrons. A cation forms by losing electrons, and an anion forms by gaining electrons.

Takeaway: Identify the element from protons, calculate neutrons from , and adjust the electron count according to charge.

Isotopes and Average Atomic Mass

Isotopes are atoms of the same element with different numbers of neutrons. For example, carbon-12 and carbon-13 each contain 66 protons, but carbon-12 has 66 neutrons and carbon-13 has 77.

The atomic mass shown on a periodic table is usually a weighted average of the naturally occurring masses:

average atomic mass=∑i(fractional abundancei)(isotopic massi)\text{average atomic mass}=\sum_i(\text{fractional abundance}_i)(\text{isotopic mass}_i)

Convert each percentage to a decimal before using it. Suppose an element has the following isotopes:

  • mass 10.0129 u10.0129\,\mathrm{u}, abundance 19.9%19.9\%;

  • mass 11.0093 u11.0093\,\mathrm{u}, abundance 80.1%80.1\%.

The calculation is:

mˉ=(0.199)(10.0129 u)+(0.801)(11.0093 u)=10.811 u\begin{aligned} \bar m&=(0.199)(10.0129\,\mathrm{u})+(0.801)(11.0093\,\mathrm{u})\\ &=10.811\,\mathrm{u} \end{aligned}

The result is closer to 11 u11\,\mathrm{u} because the second is more abundant. The atomic mass unit, u\mathrm{u}, is convenient for expressing the masses of individual atoms.

Takeaway: Isotopic composition determines the periodic-table average, so the average is pulled toward the mass of the more abundant .

Energy Levels and Electron Configurations

Electrons occupy principal energy levels identified by n=1,2,3,…n=1,2,3,\ldots. Each principal level contains subshells:

  • The ss subshell has one orbital and holds a maximum of 22 electrons.

  • The pp subshell has three orbitals and holds a maximum of 66 electrons.

  • The dd subshell has five orbitals and holds a maximum of 1010 electrons.

  • The ff subshell has seven orbitals and holds a maximum of 1414 electrons.

A principal energy level can hold a maximum of:

2n22n^2

The third level therefore holds a maximum of 2(3)2=182(3)^2=18 electrons.

Three rules guide electron placement:

  1. The Aufbau principle places electrons in available orbitals of lower energy before higher-energy orbitals.

  2. The Pauli exclusion principle limits each orbital to two electrons with opposite spins.

  3. Hund’s rule places electrons singly in equal-energy orbitals before pairing them.

The usual filling sequence is:

1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p

Examples of configurations include:

  • Hydrogen, Z=1Z=1: 1s11s^1.

  • Carbon, Z=6Z=6: 1s2 2s2 2p21s^2\,2s^2\,2p^2.

  • Oxygen, Z=8Z=8: 1s2 2s2 2p41s^2\,2s^2\,2p^4.

  • Sodium, Z=11Z=11: 1s2 2s2 2p6 3s11s^2\,2s^2\,2p^6\,3s^1, or [Ne]3s1[\mathrm{Ne}]3s^1.

Some transition metals have exceptions to the simplest filling order. Chromium is commonly written as [Ar]3d54s1[\mathrm{Ar}]3d^5 4s^1. When transition-metal cations form, electrons are generally removed from the highest principal energy level first. Thus, Fe\mathrm{Fe} is [Ar]3d64s2[\mathrm{Ar}]3d^6 4s^2, while Fe2+\mathrm{Fe^{2+}} is [Ar]3d6[\mathrm{Ar}]3d^6.

Takeaway: Build configurations by electron count, orbital energy, and the three placement rules; then verify that all superscripts add to the correct number of electrons.

and Periodic Organization

The periodic table is arranged by increasing . Its horizontal rows are periods, and its vertical columns are groups. Elements in the same group often have similar chemical properties because they have related valence-electron configurations.

For main-group elements, common patterns include:

  • Group 1: ns1ns^1, often forming 1+1+ ions.

  • Group 2: ns2ns^2, often forming 2+2+ ions.

  • Group 13: ns2np1ns^2np^1, often forming 3+3+ compounds.

  • Group 14: ns2np2ns^2np^2, often sharing electrons.

  • Group 15: ns2np3ns^2np^3, often forming three bonds or gaining three electrons.

  • Group 16: ns2np4ns^2np^4, often forming 2−2- ions or two bonds.

  • Group 17: ns2np5ns^2np^5, often forming 1−1- ions.

  • Group 18: ns2np6ns^2np^6, generally showing low chemical reactivity.

The table is also divided into blocks according to the subshell being filled. The ss block is mainly groups 11 and 22, the pp block is groups 1313 through 1818, the dd block contains transition elements, and the ff block contains the lanthanides and actinides.

Hydrogen is placed in group 11 because it has one electron, but it is a nonmetal and does not behave like an alkali metal in every situation. Helium is placed in group 1818 because its first energy level is filled and especially stable, even though its configuration is 1s21s^2.

Takeaway: Group position and valence- provide a first prediction of common charges, bonding patterns, and reactivity.

Periodic Trends and Their Causes

Periodic properties result from the interaction of nuclear charge, electron shielding, electron–electron repulsion, and the principal energy level of the outer electrons.

can be approximated by:

Zeff≈Z−shieldingZ_{\mathrm{eff}}\approx Z-\text{shielding}

Across a period, proton number increases while added electrons generally enter the same principal energy level. therefore usually increases. Down a group, additional energy levels increase both distance from the nucleus and shielding.

These ideas explain the major trends:

  • : generally decreases from left to right and increases from top to bottom. Sodium is larger than chlorine in period 33, while potassium is larger than sodium in group 11.

  • Ionic radius: cations are generally smaller than their neutral atoms because electrons are removed, while anions are generally larger because added electrons increase repulsion. Thus, r(Na+)<r(Na)r(\mathrm{Na^+})<r(\mathrm{Na}) and r(Cl−)>r(Cl)r(\mathrm{Cl^-})>r(\mathrm{Cl}).

  • : generally increases across a period and decreases down a group. It is the energy required for X(g)→X+(g)+e−\mathrm{X(g)\rightarrow X^+(g)+e^-}. A large and small radius make an electron harder to remove.

  • : describes the energy change for X(g)+e−→X−(g)\mathrm{X(g)+e^-\rightarrow X^-(g)}. Halogens often have favorable electron affinities, although subshell stability and electron repulsion produce exceptions.

  • : generally increases upward and to the right. It describes how strongly an atom in a bond attracts shared electrons.

  • Metallic character: generally increases downward and to the left. Metals more readily lose electrons, nonmetals more often gain or share them, and metalloids have intermediate properties.

For an isoelectronic series, each species has the same number of electrons. The species with more protons is smaller because its electrons experience greater nuclear attraction. The approximate largest-to-smallest order for O2−\mathrm{O^{2-}}, F−\mathrm{F^-}, Ne\mathrm{Ne}, Na+\mathrm{Na^+}, and Mg2+\mathrm{Mg^{2+}} is the order listed.

Takeaway: Across a period, increasing usually pulls electrons inward; down a group, added energy levels and shielding usually make atoms larger and their outer electrons easier to remove.

Atomic Structure, Bonding, and Reactivity

Valence-electron arrangements connect atomic structure to ions, bonds, and reactivity.

Sodium has the configuration Na:[Ne]3s1\mathrm{Na}:[\mathrm{Ne}]3s^1. Losing its single valence electron produces Na+:[Ne]\mathrm{Na^+}:[\mathrm{Ne}]. Chlorine has Cl:[Ne]3s23p5\mathrm{Cl}:[\mathrm{Ne}]3s^2 3p^5 and tends to gain one electron, producing Cl−:[Ne]3s23p6=[Ar]\mathrm{Cl^-}:[\mathrm{Ne}]3s^2 3p^6=[\mathrm{Ar}]. The electrostatic attraction between Na+\mathrm{Na^+} and Cl−\mathrm{Cl^-} contributes to ionic sodium chloride.

Atoms can also share electrons through covalent bonds. Carbon has four and commonly forms four covalent bonds. Oxygen has six and commonly forms two bonds or gains two electrons. Valence-electron arrangements help predict formulas, bonding patterns, molecular geometry, and polarity.

Reactivity follows periodic properties. Alkali-metal reactivity generally increases down the group because the single valence electron is farther from the nucleus and easier to remove. Halogen reactivity generally decreases down the group because increasing size and shielding weaken the attraction for an added electron.

Consider magnesium and chlorine. Magnesium has Z=12Z=12, configuration [Ne]3s2[\mathrm{Ne}]3s^2, and two . Chlorine has Z=17Z=17, configuration [Ne]3s23p5[\mathrm{Ne}]3s^2 3p^5, and seven . Because both are in period 33, their occupy the same principal energy level. Chlorine has more protons and a larger , so it has a smaller radius, higher , and stronger attraction for electrons than magnesium. Magnesium tends to form Mg2+\mathrm{Mg^{2+}}, while chlorine tends to form Cl−\mathrm{Cl^-}, helping explain the formation of ionic MgCl2\mathrm{MgCl_2}.

Takeaway: explains whether an atom is likely to lose, gain, or share electrons, while periodic trends explain how strongly it does so.

A Strategy for Solving Atomic-Structure Problems

Use the following sequence to solve quantitative and comparative problems:

  1. Identify the element from its .

  2. Determine protons, neutrons, and electrons. For an , use q=protons−electronsq=\text{protons}-\text{electrons}.

  3. Write the and check that its superscripts sum to the electron count.

  4. Locate the element’s group, period, and block on the periodic table.

  5. Select the relevant trend and explain it using nuclear charge, shielding, radius, energy levels, or .

  6. Check units and significant figures. Isotopic masses are commonly expressed in u\mathrm{u}, ionization energies in kJ mol−1\mathrm{kJ\,mol^{-1}}, and abundances as percentages or decimal fractions.

For a comparison, do not merely state that one property is larger. Connect the observation to a cause. For example, if two elements are in the same period, their occupy the same principal energy level. The element with more protons generally has a larger , which tends to produce a smaller and higher .

For calculations, convert percentages to fractions, multiply each mass by its fractional abundance, and add the contributions:

mˉ=∑ifimi\bar m=\sum_i f_i m_i

For calculations, determine the proton count from the element, calculate neutrons from A−ZA-Z, and use the charge to determine electrons. Then write the configuration for that electron count rather than for the neutral atom.

Final checklist:

  • Did you distinguish from ?

  • Did you account for charge when counting electrons?

  • Do configuration superscripts add correctly?

  • Did you identify the ?

  • Did you explain a trend using and shielding?

  • Did you include appropriate units and precision?

Overall takeaway: Atomic structure is a connected system: proton number identifies the element, determines valence behavior, and nuclear attraction and shielding produce the periodic trends used to predict chemical behavior.