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10/14 Chemical Kinetics Free Online FlashCards

Study 10/14 Chemical Kinetics with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What does chemical kinetics study?

Back

Chemical kinetics studies how fast reactions occur and how they proceed at the molecular level.

02
Front

How are stoichiometric rates related?

Back

For aA + bB → cC + dD, rate = −(1/a)Δ[A]/Δt = −(1/b)Δ[B]/Δt = (1/c)Δ[C]/Δt = (1/d)Δ[D]/Δt.

03
Front

What do exponents in a rate law represent?

Back

In rate = k[A]^m[B]^n, m and n are the orders in A and B; m + n is the overall order.

04
Front

How does rate = k[A][B]² respond to doubled concentrations?

Back

For rate = k[A][B]^2, doubling [A] doubles the rate, while doubling [B] quadruples it.

05
Front

What are the general units of a rate constant?

Back

For an overall order r, the rate constant has units [k] = M^(1−r) s^−1.

06
Front

Which integrated law and plot identify first-order kinetics?

Back

For a first-order reaction, ln[A]t = ln[A]0 − kt, and a plot of ln[A] versus t is linear with slope −k.

07
Front

Which integrated law and plot identify second-order kinetics?

Back

For a second-order reaction, 1/[A]t = 1/[A]0 + kt, and a plot of 1/[A] versus t is linear with slope +k.

08
Front

What is the first-order half-life formula?

Back

For a first-order reaction, t1/2 = 0.693/k. Therefore, its half-life does not depend on [A]0.

09
Front

What is a reaction intermediate?

Back

An intermediate is formed in one elementary step and consumed in a later step; it cancels when the steps are added.

10
Front

What does molecularity describe?

Back

Molecularity is the number of reactant particles involved in one elementary step: one is unimolecular, two bimolecular, and three termolecular.

11
Front

What two tests must a proposed mechanism satisfy?

Back

A proposed mechanism must add to the observed overall equation and produce the experimentally determined rate law.

12
Front

What makes a collision successful?

Back

A successful collision requires contact, sufficient energy to overcome Ea, and a suitable orientation for bonds to break and form.