Free Online Flashcard Deck

8 - Momentum, Impulse, and Collisions Free Online FlashCards

Study 8 - Momentum, Impulse, and Collisions with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

How is a system’s total momentum calculated?

Back

The total momentum of a system is the vector sum of all particle momenta: p⃗system=∑imiv⃗i\vec p_{\text{system}}=\sum_i m_i\vec v_i.

02
Front

What is the impulse-momentum theorem?

Back

Impulse equals the change in momentum: J⃗=Δp⃗=p⃗f−p⃗i\vec J=\Delta\vec p=\vec p_f-\vec p_i. For constant force, J⃗=F⃗netΔt\vec J=\vec F_{\text{net}}\Delta t.

03
Front

How is impulse found from a force-time graph?

Back

For a varying force, impulse is the area under the force-versus-time graph: J⃗=∫F⃗ dt\vec J=\int \vec F\,dt.

04
Front

Why do airbags reduce average collision force?

Back

For a fixed change in momentum, increasing collision time decreases average force because Favg=ΔpΔtF_{\text{avg}}=\frac{\Delta p}{\Delta t}.

05
Front

When is total momentum conserved?

Back

If the net external impulse is zero, a system’s total momentum remains constant: p⃗initial=p⃗final\vec p_{\text{initial}}=\vec p_{\text{final}}.

06
Front

What effect do internal forces have on total momentum?

Back

Internal forces act between objects inside the chosen system. They can transfer momentum among those objects but cannot change the system’s total momentum by themselves.

07
Front

What defines an elastic collision?

Back

In an elastic collision, both total momentum and total kinetic energy are conserved. The kinetic energy of an individual object may still change.

08
Front

What defines an inelastic collision?

Back

An inelastic collision conserves momentum but not total kinetic energy. The lost kinetic energy becomes internal energy, sound, deformation, or other forms.

09
Front

What happens in a perfectly inelastic collision?

Back

In a perfectly inelastic collision, the objects stick together and share one final velocity: vf=m1v1i+m2v2im1+m2v_f=\frac{m_1v_{1i}+m_2v_{2i}}{m_1+m_2}.

10
Front

Why does a launcher recoil when firing a projectile?

Back

A launcher recoils opposite the projectile so the total momentum remains zero: 0=mpvp+mLvL0=m_pv_p+m_Lv_L. Thus, vL=−mpvpmLv_L=-\frac{m_pv_p}{m_L}.

11
Front

How is the center of mass found for two particles?

Back

For two particles on one axis, xCM=m1x1+m2x2m1+m2x_{\text{CM}}=\frac{m_1x_1+m_2x_2}{m_1+m_2}. The center of mass lies closer to the more massive object.

12
Front

How are total momentum and center-of-mass velocity related?

Back

Total momentum relates to center-of-mass velocity by p⃗system=Mv⃗CM\vec p_{\text{system}}=M\vec v_{\text{CM}}, where MM is the system’s total mass.