Free Online Flashcard Deck

4 Basic Thermodynamic Processes Free Online FlashCards

Study 4 Basic Thermodynamic Processes with 12 free online flashcards. Review key terms, definitions, and concepts with this interactive flashcard deck.

12 cards
01
Front

What does a thermodynamic process describe?

Back

A thermodynamic process describes a system changing from one equilibrium state to another.

02
Front

What equation relates pressure, volume, and temperature for an ideal gas?

Back

For a fixed amount of ideal gas, the ideal-gas law is pV=nRTpV=nRT.

03
Front

What is the first law using work done by the gas as positive?

Back

With WW defined as work done by the gas and QQ as heat added to it, the first law is ΔU=Q−W\Delta U=Q-W.

04
Front

How is work represented on a pressure–volume diagram?

Back

For a quasi-static process, work is W=∫V1V2p dVW=\int_{V_1}^{V_2}p\,dV, the signed area under the curve on a pressure–volume diagram.

05
Front

What determines an ideal gas’s internal-energy change?

Back

An ideal gas’s internal energy depends only on temperature. For constant heat capacity, ΔU=nCV(T2−T1)\Delta U=nC_V(T_2-T_1).

06
Front

How are CPC_P, CVC_V, and γ\gamma related for an ideal gas?

Back

For an ideal gas, CP−CV=RC_P-C_V=R, and the heat-capacity ratio is γ=CP/CV\gamma=C_P/C_V.

07
Front

What is the work in an isobaric ideal-gas process?

Back

At constant pressure, W=p(V2−V1)=nR(T2−T1)W=p(V_2-V_1)=nR(T_2-T_1).

08
Front

How is heat transfer calculated for an isobaric process?

Back

For an isobaric process, the heat transfer is Q=nCP(T2−T1)Q=nC_P(T_2-T_1).

09
Front

What are work and heat transfer in an isochoric process?

Back

At constant volume, W=0W=0, so Q=ΔU=nCV(T2−T1)Q=\Delta U=nC_V(T_2-T_1).

10
Front

What happens to pVpV and internal energy in an isothermal ideal-gas process?

Back

For a fixed amount of ideal gas at constant temperature, pV=nRTpV=nRT remains constant, and ΔU=0\Delta U=0.

11
Front

What are work and heat transfer in a reversible isothermal process?

Back

For a reversible isothermal process, W=nRTln⁡ ⁣(V2V1)W=nRT\ln\!\left(\frac{V_2}{V_1}\right) and Q=WQ=W.

12
Front

What condition defines an adiabatic process?

Back

An adiabatic process has no heat transfer: Q=0Q=0.