3 The First Law and Energy Balances

Learn how energy conservation is expressed for closed systems and flowing control volumes, and how to apply the balances under stated assumptions.

The first law for closed systems

The applies conservation of energy to thermodynamic systems: energy may cross a system boundary or change form, but it cannot be created or destroyed.

For a , use the convention that heat transferred into the system is positive and work done by the system is positive. With this convention, the energy balance is

ΔE=Q−W,\Delta E=Q-W,

where the total energy is

E=U+KE+PE.E=U+KE+PE.

Here, UU is , KEKE is macroscopic kinetic energy, and PEPE is gravitational potential energy. If changes in motion and elevation are negligible, the balance reduces to ΔU=Q−W\Delta U=Q-W. Heat and work describe energy crossing the boundary; neither is a property stored in the system. , in contrast, is a property of the system's state.

Applying the closed-system balance

A contains a fixed amount of matter, so mass does not cross its boundary. Between an initial state and a final state, its balance is

E2−E1=Q−W.E_2-E_1=Q-W.

For example, if a gas receives 500 kJ500\ \text{kJ} of heat and does 180 kJ180\ \text{kJ} of work, and changes in kinetic and potential energy are negligible, then

ΔU=500−180=320 kJ.\Delta U=500-180=320\ \text{kJ}.

The gas's increases by 320 kJ320\ \text{kJ}. If work is done on the system instead, that work is negative under this sign convention.

and

accounts for energy at the molecular level, including molecular motion and interactions. Specific is per unit mass:

u=Um.u=\frac{U}{m}.

Changes in depend on the initial and final states, not on the path connecting them.

is defined by

H=U+pV,h=u+pv,H=U+pV, \qquad h=u+pv,

where pp is pressure, VV is volume, and vv is specific volume. is a state property. Its pvpv term is useful for flowing fluids because it accounts for the pressure-related work needed to push fluid into or out of a . Flowing mass therefore transports across the boundary.

Energy balance for a

A is a chosen region in space through which mass may flow. Its energy can change through heat and work transfer and through energy entering or leaving with flowing matter.

The general rate balance is

dEcvdt=Q˙−W˙+∑inm˙(h+V22+gz)−∑outm˙(h+V22+gz).\frac{dE_{\mathrm{cv}}}{dt} =\dot Q-\dot W +\sum_{\mathrm{in}}\dot m\left(h+\frac{V^2}{2}+gz\right) -\sum_{\mathrm{out}}\dot m\left(h+\frac{V^2}{2}+gz\right).

Here, Q˙\dot Q is the heat-transfer rate into the , and W˙\dot W is the work rate out of it. The mass-flow rate is m˙\dot m, the flow speed is VV, and the elevation is zz. The work term includes work crossing the control surface, such as shaft work. The specific energy carried by flowing matter includes , kinetic energy, and potential energy.

Steady-flow balances and a turbine

At , energy stored inside the does not change, so dEcv/dt=0dE_{\mathrm{cv}}/dt=0. For one inlet and one outlet, when changes in kinetic and potential energy are negligible, the balance becomes

Q˙−W˙+m˙hin−m˙hout=0.\dot Q-\dot W+\dot m h_{\mathrm{in}}-\dot m h_{\mathrm{out}}=0.

For an adiabatic turbine, Q˙=0\dot Q=0. If changes in speed and elevation are also negligible, its shaft power output is

W˙=m˙(hin−hout).\dot W=\dot m(h_{\mathrm{in}}-h_{\mathrm{out}}).

For example, with m˙=2 kg/s\dot m=2\ \text{kg/s}, hin=3200 kJ/kgh_{\mathrm{in}}=3200\ \text{kJ/kg}, and hout=2600 kJ/kgh_{\mathrm{out}}=2600\ \text{kJ/kg},

W˙=1200 kJ/s=1200 kW.\dot W=1200\ \text{kJ/s}=1200\ \text{kW}.

The decrease in the fluid's supplies the turbine's work output.

A practical approach

Use a consistent sequence when applying an energy balance:

  1. Define the system or and identify what crosses its boundary.

  2. Choose a consistent sign convention for heat and work.

  3. Write the full energy balance before neglecting any terms.

  4. Apply the stated assumptions, such as a , , adiabatic operation, or negligible changes in speed and elevation.

  5. Check units and interpret the sign of the result.

The appropriate balance depends on what crosses the boundary and which stated assumptions apply. For closed systems, energy transfer is represented by heat and work; for control volumes, energy carried by mass must also be included.