A heat engine absorbs and rejects per cycle. What is its thermal efficiency? Enter the value as a percentage.
5 The Second Law and Entropy Online Quiz Questions
Use this free practice quiz with 20 questions to review 5 The Second Law and Entropy, test your knowledge, and prepare for your next test or exam.
A reversible engine operates between reservoirs at 750K and 300K. What is its maximum thermal efficiency? Enter a decimal, not a percentage.
A heat pump delivers 900kJ to a warm region while requiring 300kJ of input work. What is its coefficient of performance?
A system undergoes a reversible isothermal process at 400K and absorbs 1200J of heat. What is its entropy change?
Which statement describes the spontaneous direction of heat transfer between two objects at different temperatures?
- A
Heat flows spontaneously from a cooler object to a warmer object.
- B
Heat flows spontaneously from a warmer object to a cooler object.
- C
Heat can flow only when work is supplied.
- D
Heat flow always converts all transferred energy into work.
A heat engine absorbs 900J from a hot reservoir and rejects 360J to a cold reservoir each cycle. How much net work does it produce per cycle?
- A
360 J
- B
500 J
- C
540 J
- D
1,260 J
Why can a refrigerator or heat pump have a coefficient of performance greater than 1 without violating energy conservation?
- A
A COP can exceed 1 because the device moves heat using supplied work rather than converting work entirely into heat.
- B
A COP can exceed 1 only when the device creates energy.
- C
A COP is the fraction of input heat converted into work, so it cannot exceed 1.
- D
A COP can exceed 1 only if the cold region is warmer than the hot region.
A refrigerator lowers the entropy of its cold interior. Which statement explains how this can be consistent with the second law?
- A
No: the entropy of every individual system must always increase.
- B
No: the second law requires entropy to remain constant in every process.
- C
Yes: any decrease in system entropy is allowed, even if total entropy decreases.
- D
Yes: its surroundings can gain at least as much entropy as the system loses, keeping the total entropy change nonnegative.
A system undergoes an irreversible process between two states. How can its entropy change be determined?
- A
Use only the heat transferred during the actual irreversible process, divided by the initial temperature.
- B
Calculate ΔS along a reversible path between the same initial and final states.
- C
Entropy change cannot be calculated for an irreversible process.
- D
Use the work done during the actual process divided by the final temperature.
A real heat engine operating between two reservoirs can have an efficiency greater than the Carnot limit for those reservoir temperatures.
- A
True
- B
False
A heat pump and a refrigerator operate using the same cycle. If the heat-pump coefficient of performance is 4, what is the refrigerator coefficient of performance?
- A
1
- B
2
- C
3
- D
4
What is the effect of irreversible processes on energy conversion, according to the second law, while still respecting the first law?
- A
Energy is conserved, but irreversible entropy generation makes less of it available for conversion into useful work.
- B
Energy disappears when entropy is generated, so the first law no longer applies.
- C
Irreversibility increases the maximum possible work output by eliminating heat rejection.
- D
Entropy generation changes only the amount of energy, not its availability for useful work.
A proposed cyclic engine absorbs heat from a single reservoir and converts all of that heat into work, returning to its initial state after each cycle. Which assessment is correct?
- A
The proposal violates the first law because the engine's energy would increase on every cycle.
- B
The proposal is ruled out by the second law, even though the energy balance alone may be satisfied.
- C
The proposal is possible if the engine operates slowly enough.
- D
The proposal is possible as long as the reservoir is sufficiently hot.
Select all statements that accurately describe refrigerators and heat pumps.
- A
A refrigerator removes heat from the cold region.
- B
A heat pump focuses on delivering heat to the warmer region.
- C
For either device, the input work satisfies Win=QH−QC.
- D
A refrigerator and a heat pump move heat from cold to hot without requiring work.
- E
A refrigerator's primary useful effect is delivering heat to the warmer region.
Select all statements that correctly distinguish a heat engine from a refrigerator or heat pump.
- A
A heat engine absorbs heat from a hot reservoir and rejects some heat to a colder reservoir.
- B
A refrigerator uses input work to move heat from a colder region to a warmer one.
- C
A refrigerator produces net work by moving heat from cold to hot.
- D
A heat pump uses the same kind of cycle as a refrigerator but focuses on delivering heat to the warmer region.
- E
A heat engine and a refrigerator both use input work to move heat from cold to hot.
True or false: Even if an actual process is irreversible, the entropy change between its initial and final states can be determined using a reversible path connecting those states.
- A
True
- B
False
True or false: A refrigerator and a heat pump both require input work to move heat from a colder region to a warmer region.
- A
True
- B
False
A device uses input work to keep a food compartment cold by removing heat from it. This device is a .
A building system uses input work to move heat from outdoors into the building and is designed primarily to deliver heat indoors. This device is a .
Explain why a reversible path can be used to determine the entropy change between two states even when the actual process connecting them is irreversible.