5 The Second Law and Entropy

Understand how the second law constrains heat-to-work conversion, how entropy describes process direction, and how reservoir temperatures set ideal engine and appliance performance limits.

What the restricts

The expresses energy conservation: energy transferred as heat or work changes a system’s energy but is not created or destroyed. The adds a restriction that the first law alone cannot provide: it determines which energy transformations can occur naturally and limits how much heat can become useful work.

Heat flows spontaneously from a warmer object to a cooler one. The reverse transfer is possible only when work is supplied, as in a . Similarly, a cyclic engine cannot take heat from a single reservoir and convert it all into work. These are equivalent forms of the .

Heat engines and efficiency

A operates in a cycle, absorbing heat from a hot reservoir, producing work, and rejecting some heat to a colder reservoir. Let QHQ_H be the heat absorbed from the hot reservoir, QCQ_C the magnitude of the heat rejected to the cold reservoir, and WoutW_{out} the net work produced.

Because the engine returns to its initial state each cycle, its change in internal energy over a cycle is zero. The first law therefore gives

Wout=QH−QC.W_{out}=Q_H-Q_C.

The engine’s is the fraction of input heat converted to work:

η=WoutQH=1−QCQH.\eta=\frac{W_{out}}{Q_H}=1-\frac{Q_C}{Q_H}.

The requires QC>0Q_C>0 for any cyclic engine operating between ordinary hot and cold reservoirs. Thus, no such engine can convert all its absorbed heat into work.

Refrigerators and heat pumps

A uses work to move heat from a colder region to a warmer one. A uses the same kind of cycle but focuses on delivering heat to the warmer region. For both devices, QCQ_C is removed from the cold region, QHQ_H is delivered to the hot region, and the required input work is

Win=QH−QC.W_{in}=Q_H-Q_C.

Their performance is measured by a (COP), not by engine efficiency:

COPR=QCWin,COPHP=QHWin.\mathrm{COP}_R=\frac{Q_C}{W_{in}},\qquad \mathrm{COP}_{HP}=\frac{Q_H}{W_{in}}.

A COP can exceed 11: it compares heat moved with work supplied, and the device moves heat rather than converting work entirely into heat. For the same cycle, COPHP=COPR+1\mathrm{COP}_{HP}=\mathrm{COP}_R+1.

and process direction

, represented by SS, is a thermodynamic state property that helps express the quantitatively. For a reversible path between two states,

ΔS=∫initialfinalδQrevT,\Delta S=\int_{\text{initial}}^{\text{final}}\frac{\delta Q_{rev}}{T},

where TT is absolute temperature in kelvins. is a state function, so this reversible-path calculation gives the change between the states even when the actual process is irreversible.

For an isolated system—or, more generally, the system and its surroundings taken together—the states

ΔStotal≥0.\Delta S_{total}\geq 0.

stays constant in an ideal reversible process and increases in an irreversible one. A system’s own can decrease, provided the increase elsewhere is at least as large. For instance, a lowers the of its cold interior, but its work input and heat rejection cause a net increase in the surroundings and the overall process.

Reversible limits and real devices

A reversible engine operating between hot and cold reservoirs at temperatures THT_H and TCT_C has the greatest possible efficiency for those temperatures. Its efficiency is the :

ηmax=1−TCTH.\eta_{max}=1-\frac{T_C}{T_H}.

The temperatures must be in kelvins. Any real engine operating between the same reservoirs has efficiency no greater than this limit; friction, finite-temperature differences during heat transfer, and other irreversible effects make it lower.

The corresponding maximum COPs for ideal reversible refrigerators and heat pumps are

COPR,max=TCTH−TC,COPHP,max=THTH−TC.\mathrm{COP}_{R,max}=\frac{T_C}{T_H-T_C},\qquad \mathrm{COP}_{HP,max}=\frac{T_H}{T_H-T_C}.

For example, between reservoirs at 600 K600\,\mathrm{K} and 300 K300\,\mathrm{K}, the maximum engine efficiency is 1−300600=0.501-\frac{300}{600}=0.50, or 50%50\%. The ideal COP is 300600−300=1\frac{300}{600-300}=1, while the ideal heat-pump COP is 600600−300=2\frac{600}{600-300}=2. Real devices perform below these limits.

The does not say that energy disappears: the first law still accounts for all of it. Rather, energy transferred as heat becomes less fully available for conversion into useful work as irreversible processes generate . The temperature difference between reservoirs matters because it determines the theoretical opportunity to produce work.